The correct question is:
Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)
Answer:
x = c1e^(-t) + c2e^(3t)
is a solution to the differential equation
x''- 2x' - 3x = 0
Step-by-step explanation:
We need to verify that
x = c1e^(-t) + c2e^(3t)
is a solution to the differential equation
x''- 2x' - 3x = 0
We differentiate
x = c1e^(-t) + c2e^(3t)
twice in succession, and substitute the values of x, x', and x'' into the differential equation
x''- 2x' - 3x = 0
and see if it is satisfied.
Let us do that.
x = c1e^(-t) + c2e^(3t)
x' = -c1e^(-t) + 3c2e^(3t)
x'' = c1e^(-t) + 9c2e^(3t)
Now,
x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]
= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)
= 0
Therefore, the differential equation is satisfied, and hence, x is a solution.
Answer:
Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.
Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity
Step-by-step explanation:
Given that the vector b = (-2, -1) can be written as follows;
b = -2·i - j, we have;
= √((-2)² + (-1)²) = √5
Therefore, we have;
The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)
Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2
The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))
Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.
Answer:
y=45
x=9
z= 9 root 2
Step-by-step explanation:
This is a right isosceles triangle, so
y=45
x=9
z= 9 root 2
9²+9²=z²
81+81=z²
162=z²
√162=z
z=9√2
Hey there! :)
Answer:
h(x) = 3x² - 7x - 6
Step-by-step explanation:
Calculate h(x) by adding the two polynomials:
h(x) = f(x) + g(x):
h(x) = x² - 3x + 5 + 2x² - 4x - 11
Combine like terms:
h(x) = 3x² - 7x - 6
