Your answer would be 15.6
Answer:
1. wire is approx. 143.96 ft
2. pole is approx. 106.55 ft
Step-by-step explanation:
Mapping the information on the SOHCAHTOA picture below:
Φ = 46
wire = hypotenuse
adjacent side = 100
CAH is most suitable:
cos 46° = 100/wire => wire = 100/cos 46 ≈ 143.96
pole = opposite side + 3
TOA is most suitable:
tan 46° = (pole-3)/100 => pole = 3 + 100 * tan 46 ≈ 106.55
To find out time interval δt we need to substract initial time from the final time. In this question first number in the coordinates representes time:
δt=50 - 0
δt= 50s
TIme interval is 50s.
Answer:
t = 21d
Step-by-step explanation:
Here tension and distance are denoted t by d and respectively. Since t varies directly with d , then the relation between t and d is k=td Given that, for the tension 42 pounds, the spring is stretched 2 inches. Substituting t = 42 and d= 2 into t = kd find the value of k . Therefore,
42= K (2)

K= 21
Thus the relationship is t = 21d
(Hope this helps can I pls have brainlist (crown)☺️)
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