In the question it gives you what "s" is which is 3, so plug that in instead of s.
c = 25s²
c = 25(3²)
c = 25(9)
c = 225 << your answer
hope this helps, God bless!
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➷ 15/9 as a decimal is 0.6 (recurring)
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The answer i believe is 1
Let a be the amount needed of 70% pure antifreeze, and let b be the amount needed of 95% pure antifreeze.
0.7a + 0.95b = 180 * 0.9 .........(1)
a + b = 180 .............................(2)
b = 180 - a ..............................(3)
Plugging the expression for b in equation (3) into equation (1), we get:
0.7a + 0.95(180 - a) = 162 ......(4)
Solving equation (4) gives the value a = 36, and plugging this value for a into equation (2) we get b = 144.
Amounts needed are therefore 36 gallons of 70% pure antifreeze and 144 gallons of 95% pure antifreeze.
Answer:
B
Step-by-step explanation:
30-3.12=26.88 divide that by 4 and you get 6.72