All categories

3 years ago

A penny weighs about 0.1 oz. how much is a pound of pennies worth

1 answer:

7 0

<span>1. </span><span>A penny weighs about 0.1 oz.
Now, we need to find the weights of pennies in pounds
=> always remember that in every 1 oz, there is 0.0625 pounds.
Since 0.1 is 1/10 of 1 oz, we need to find the value of it in pounds.
=> 0.0625 pounds / 10
=> 0.0625 pounds.
Therefore, in 0.1 oz of penny is equivalent to 0.00625 pounds.
In problem like this, before determining the answer, you need to make sure that both unit of measurements are the same. If not, then try to convert.</span>

You might be interested in

He school that Tony goes to is selling tickets to a play. On the first day of ticket sales the school

UNO [17]

Answer:

The price of 1 adult ticket is 12 dollars, and the price of a ticket for one student is 7 dollars

Step-by-step explanation:

Make a system of equations for the two days that the play was shown.

Let x = the price of an adult ticket

Let y = the price of a student ticket

For the first day:

For the second day:

Now, we can solve using the elimination method. Multiply the first equation by 2 and the second equation by 9. Then swap the order of the equations.

<h3>18x+63y= 657</h3><h3>-</h3><h3>18x+16y= 328</h3><h3>0x+ 47y= 329</h3><h3>divide both sides by 47</h3><h3>y = 7</h3><h3>Plug in 7 for y for the 2nd equation</h3><h3>2x+7(7)=73</h3><h3>2x+49=73</h3><h3>subtract 49 from both sides</h3><h3>2x= 24</h3><h3>divide both sides by 2</h3><h3>x = 12 </h3><h3>Check:</h3><h3>2(12)+7(7)=73</h3><h3>24+49= 73!</h3>

8 0

2 years ago

Read 2 more answers

Solve: 2x2-x = 21 {-7/2,3} {-3, 7/2}

Sergio039 [100]

Answer:

The answer is (-3,7/2)

Step-by-step explanation:

$2 {x}^{2} - x - 21 = 0 \\ (2x - 7)(x + 3) = 0 \\ 2x - 7 = 0 \: \: \: or \: \: x + 3 = 0 \\ x = \frac{7}{2} \: \: and \: x = - 3$

I am a math teacher If you need any explanation you can communicate with me on Whats on this number +201557831028

4 0

3 years ago

I FORGOT THE LAST ONE

zalisa [80]

I think it’s 3.2 but I don’t know

5 0

3 years ago

Read 2 more answers

What is the value of y?

Gelneren [198K]

Answer:

try 70

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bx%2By%3D1%7D%20%5Catop%20%7Bx-2y%3D4%7D%7D%20%5Cright.%20%5C%5C%5Clef

brilliants [131]

Answer:

<em>(c)</em> $\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

Step-by-step explanation:

<u>Cramer's Rule</u>

It's a predetermined sequence of steps to solve a system of equations. It's a preferred technique to be implemented in automatic digital solutions because it's easy to structure and generalize.

It uses the concept of determinants, as explained below. Suppose we have a 2x2 system of equations like:

$\displaystyle \left \{ {{ax+by=p} \atop {cx+dy=q}} \right.$

We call the determinant of the system

$\Delta=\begin{vmatrix}a &b \\c &d \end{vmatrix}$

We also define:

$\Delta_x=\begin{vmatrix}p &b \\q &d \end{vmatrix}$

And

$\Delta_y=\begin{vmatrix}a &p \\c &q \end{vmatrix}$

The solution for x and y is

$\displaystyle x=\frac{\Delta_x}{\Delta}$

$\displaystyle y=\frac{\Delta_y}{\Delta}$

(a) The system to solve is

$\displaystyle \left \{ {{x+y=1} \atop {x-2y=4}} \right.$

Calculating:

$\Delta=\begin{vmatrix}1 &1 \\1 &-2 \end{vmatrix}=-2-1=-3$

$\Delta_x=\begin{vmatrix}1 &1 \\4 &-2 \end{vmatrix}=-2-4=-6$

$\Delta_y=\begin{vmatrix}1 &1 \\1 &4 \end{vmatrix}=4-3=3$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{3}{-3}=-1$

The solution is x=2, y=-1

(b) The system to solve is

$\displaystyle \left \{ {{4x-y=6} \atop {x-y=0}} \right.$

Calculating:

$\Delta=\begin{vmatrix}4 &-1 \\1 &-1 \end{vmatrix}=-4+1=-3$

$\Delta_x=\begin{vmatrix}6 &-1 \\0 &-1 \end{vmatrix}=-6-0=-6$

$\Delta_y=\begin{vmatrix}4 &6 \\1 &0 \end{vmatrix}=0-6=-6$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-6}{-3}=2$

The solution is x=2, y=2

$\displaystyle \left \{ {{-x+2y=0} \atop {x+2y=5}} \right.$

Calculating:

$\Delta=\begin{vmatrix}-1 &2 \\1 &2 \end{vmatrix}=-2-2=-4$

$\Delta_x=\begin{vmatrix}0 &2 \\5 &2 \end{vmatrix}=0-10=-10$

$\Delta_y=\begin{vmatrix}-1 &0 \\1 &5 \end{vmatrix}=-5-0=-5$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-10}{-4}=\frac{5}{2}$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-5}{-4}=\frac{5}{4}$

The solution is

$\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) The system to solve is

$\displaystyle \left \{ {{6x-y=-5} \atop {4x-2y=6}} \right.$

Calculating:

$\Delta=\begin{vmatrix}6 &-1 \\4 &-2 \end{vmatrix}=-12+4=-8$

$\Delta_x=\begin{vmatrix}-5 &-1 \\6 &-2 \end{vmatrix}=10+6=16$

$\Delta_y=\begin{vmatrix}6 &-5 \\4 &6 \end{vmatrix}=36+20=56$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{16}{-8}=-2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{56}{-8}=-7$

The solution is x=-2, y=-7

4 0

3 years ago