Answer:
f x y z 4y cos (< x >) y x sin z z xy k s is the hemisphere x2 y2 z2 25 z ≥ 0 oriented upward
use stokes theorem to evaluate f dr
s is the hemisphere x 2 y 2 z 2 16
consists of the top and the four sides but not the bottom of the cube with vertices oriented outward
stokes theorem triangle with vertices
f xyz x y 2 i y z 2 j z x 2 k where k is the triangle with vertices
∫ f ∙ dr c when f x y z 2xi 3zj xk and c is the triangle with vertices 0 0 0 1 1 1 and 0 0 2
s is the part of the paraboloid z 1 − x2 − y2 that lies above the xy plane oriented upward
We are given with two functions: f(x) = x + 8 and g(x) = x2 - 6x - 7. In this problem, the value of f(g(2)) is asked. We first substitute g(x) to f(x) resulting to f(x2 - 6x - 7) = x2 - 6x - 7 + 8 = x2 - 6x + 1. If x is equal to 2, then <span>f(g(2)) = 2^</span>2 - 6*2 + 1 equal to -7.
Answer: 8 movies
12 + 1.50x = 3x
Move the variables to one side
12 = 1.50x
Isolate x
8 = x
Check:
3(8)= 24
12.00 + 1.50(8) = 24
