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4 years ago

What is m∠LQK? I have to attack the file

Mathematics

2 answers:

AURORKA [14]4 years ago

7 0

$4n-15+3n=90\\
7n=105\\
n=15\\\\
\angle LQK=4\cdot15-15=60-15=45^{\circ}$

Olegator [25]4 years ago

6 0

3n+(4n-15)=90

3n+4n-15=90

7n=105

n=105/7

n=15

---------------------

Angle LQK is 4n-15

If n=15

Angle LQK = 4(15) - 15

= 60 - 15

= 45

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You have decided to invest $1000 in a savings bond that pays 4% interest, compounded semi-annually. What will the bond be worth

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$2191.12

Step-by-step explanation:

We are asked to find the value of a bond after 10 years, if you invest $1000 in a savings bond that pays 4% interest, compounded semi-annually.

$FV=C_0\times (1+r)^n$ , where,

$C_0=\text{Initial amount}$ ,

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3 years ago

Use the following compound interest formula to complete the problem. a = p (1 startfraction r over n endfraction) superscript n

Ratling [72]

The final amount that Victor will owe after one year, to the nearest cent is given by: Option C: $545.65

<h3>How to find the compound interest?</h3>

If n is the number of times the interested is compounded each year, and 'r' is the rate of compound interest annually, then the final amount after 't' years would be:

$a = p(1 + \dfrac{r}{n})^{nt}$

For this case, we're provided that:

The interest rate is r = 13.66% = 13.66/100 = 0.1366 (converted percent to decimal)

It is compounding monthly, thus, 12 times a year, or n = 12

The initial amount that the credit card of Victor has = p = $1349.34

Time for which interest was compounded = a year = 1 = t

Thus, the final amount that Victor will owe after one year to the nearest cent is calculated as;

$a = p(1 + \dfrac{r}{n})^{nt}\\\\a = 1349.34(1 + \dfrac{0.1366}{12})^{12\times 1}\\\\a = 1349.34(1.01138)^{12} \approx 1245.65 \: \rm (in \: dollars)$