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Elina [12.6K]
3 years ago
13

Solve the variable of x. 3^3^x= 1/243​

Mathematics
2 answers:
wolverine [178]3 years ago
8 0

Answer:

-5/3

Step-by-step explanation:

Create equivalent expressions in the equation that all have equal bases, then solve for x.

Alex Ar [27]3 years ago
7 0

Answer:

-5

Step-by-step explanation:

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Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

\frac{dP}{dt} = Pr

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

\frac{dP}{P} = r dt

\int \frac{dP}{P} = \int r dt

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Applying the exponential to both sides:

P(t) = Ke^{rt}

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This means that K = 300. So

P(t) = 300e^{rt}

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

P(t) = 300e^{rt}

1000 = 300e^{24r}

e^{24r} = \frac{1000}{300}

e^{24r} = \frac{10}{3}

\ln{e^{24r}} = \ln{\frac{10}{3}}

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r = \frac{\ln{\frac{10}{3}}}{24}

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P(t) = 300e^{0.05t}

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This is t for which P(t) = 500. So

P(t) = 300e^{0.05t}

500 = 300e^{0.05t}

e^{0.05t} = \frac{500}{300}

e^{0.05t} = \frac{5}{3}

\ln{e^{0.05t}} = \ln{\frac{5}{3}}

0.05t = \ln{\frac{5}{3}}

t = \frac{\ln{\frac{5}{3}}}{0.05}

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