Answer:
-2.154
Step-by-step explanation:
We are given;
Population mean; μ = 432
Sample mean; x¯ = 425
Sample size; n = 29
standard deviation; σ = 26
Hypothesis is defined as;
Null hypothesis; H0: μ ≥ 432
Alternative hypothesis: Ha: μ < 432
Formula for the test statistic since sample size is less than 30 is;
t = (x¯ - μ)/(σ/√n)
Plugging in the relevant values;
t = (425 - 432)/(26/√29)
t = -1.45
Now,we are given significance level of 0.02; our DF = n - 1 = 29 - 1 = 28
From t-table attached, we can see that at DF of 28 and significance value of 0.02, the critical value is 2.154
However, this is a left tailed test as the rejection region is to the left.
Thus, the critical value of a left tailed test is negative. Thus, in this case our critical value will be -2.154
The first part to question 8 is 2.25 and the answer to part b is 12
Answer: 
Step-by-step explanation:
1. You know that the force acting on the object varies directly with the object's acceleration. Then, by definition, you have:
Where 
is the force acting on the object, 
is the object's acceleration and 
is the constant of proportionality.
2. Keeping this on mind, you can calculate the constant of proportionality by substituting 
and 
into the equation and solving for :
3. Now, you can calculate the force when the acceleration of the object becomes 5 m/s², as following:
3. The result is:
Answer:
At the time of launch height of the object was 60 meters.
Step-by-step explanation:
An object was launched from a platform and its height was modeled by the function,
h(x) = -5x² + 20x + 60
Where x = time or duration after the launch
At the time of launch, x = 0
So, by putting x = 0 in this equation,
h(0) = -5×(0) + 20×(0) + 60
h(0) = 60
Therefore, at the time of launch height of the object was 60 meters.
there’s nothing there srry
