Written as a power of ten is 256.×10^0 or 2.56×10^1
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
Answer:
12.16 it's a continues answer tho
Transformation.. If you're referring to geometry
Answer:
y = 3x + 2
Step-by-step explanation:
Let's identify two clear points on this line. I can see (0, 2) and (-1, -1)
First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)
Plug in these values:
(-1 - 2) / (-1 - 0)
Simplify the parentheses.
= (-3) / (-1)
Simplify the fraction.
-3/-1
= 3
This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.
y = 3x + b
To find b, we want to plug in a value that we know is on this line: in this case, I will use the first point (0, 2). Plug in the x and y values into the x and y of the standard equation.
2 = 3(0) + b
To find b, multiply the slope and the input of x(0)
2 = 0 + b
Now, we are left with 0 + b.
2 = b
Plug this into your standard equation.
y = 3x + 2
This is your equation.
Hope this helps!
