The answer is TRUE.
There you go.
Answer:
Relational query language is the language that is used in the queries of the relational databases that has rows and columns in table. The user or client presents a request for gaining the information from the database. The relationships in the database are defined in numerous ways which creates the query.
This language can be procedural form or non-procedural form.The operations performed by this language are communication with the relational database, analyzing the relationships between the entities of database,splitting the request from client and then execution of that request is done by database management system(DBMS), etc.
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}
Answer:
nums = []
while True:
in = input()
if in:
nums.append(in)
else:
break
if nums:
avg = sum(nums) / len(nums)
for i in range(len(nums)):
if nums[i] == avg:
print(f"index: {i+1}")
print(nums[i])
else:
print(-1) # if there aren't any values in nums
Explanation:
Assuming that you are coding in Python 3x. The last 'else' statement is an edge case that you might want to consider, I don't know what you want to put there, but I'm just going to leave it as -1.