<span>The toolbar on the top of screen and menu bar the mean part of commands.</span>
Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) =
=
= 0.0316
For x = 120, sample proportion(p) =
=
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z <
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
Answer:
chaos among people who worked in the company.
#accepting input from user
n=int(input("Enter a number: "))
#entered number is stored in a temporary variable
temp=n
#initializng required variables
rev=0
dgt=0
#digits are reversed inside while loop
while(n>0):
dgt=n%10
rev=rev*10+dgt
n=n//10
#original number and its reverse are compared
if(temp==rev):
#if equal, it's a palindrome
print("It is a Palindrome")
else:
#if not equal, it's not a palindrome
print("It is not a Palindrome")
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