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klemol [59]
3 years ago
6

Uses of the following button in a keyboard: Prt SC, Home, Shift, Tab, Pg Up.​

Computers and Technology
1 answer:
creativ13 [48]3 years ago
4 0

Answer:

This Print Screen key is used to take the screenshots of all that is appearing on the screen, and this can then be pasted in paint and saved in some location of the computer.

The Home key takes the cursor from the current position to the top left, or the start of the file.

Shift: There are two shift keys. And they are used to print the character in the capital. And when the caps lock is busy it can be used to print in lower case. It is also used together with arrow keys to select a part of the text.

Tab: This key moves the cursor from the current location to the location which we know as tab stops ( and the very next one).

Pg Up:​ The page up is being used for scrolling up, and the distance to which limit the scrolling will take place depends upon the application you are working on.

Explanation:

Please check the answer.

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Zinaida [17]

The correct debugged code is attached below

<h3>What is a leap year </h3>

A leap year is a year with 366 days and this year occurs once every 4 years. The debugged code line of code of the program written, is as attached below. because the line of code in the question lacks some functions and symbols

Hence we can conclude that the correct debugged code is attached below.

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6 0
2 years ago
Question 1 of 30
Paha777 [63]
It’s exercise tax $5 tax on a cable television line

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7 0
3 years ago
Best gaming chairs under 150 (facts)​
adelina 88 [10]

Answer:

IKEA ÖRFJÄLL/SPORREN Swivel Chair, White, Vissle Light Green 191.623.75

Explanation:

it's Ikea

7 0
3 years ago
The strength of gravity on the Moon is 1.6
sergeinik [125]

Answer:

Mass = 80kg

Explanation:

Given

On Earth

Mass = 80kg

On the moon

g = 1.6N/kg

Required

The astronaut's mass on the moon

The mass of an object do not change base on location

So, if the mass of the astronaut is 80kg on earth, it will be 80 kg on the moon.

Hence:

Mass = 80kg

6 0
3 years ago
Write a static method called bothStart that allows the user to input two Strings and returns the String that is the longest subs
marishachu [46]

Answer:

  1.    public static String bothStart(String text1, String text2){
  2.        String s = "";
  3.        if(text1.length() > text2.length()) {
  4.            for (int i = 0; i < text2.length(); i++) {
  5.                if (text1.charAt(i) == text2.charAt(i)) {
  6.                    s += text1.charAt(i);
  7.                }else{
  8.                    break;
  9.                }
  10.            }
  11.            return s;
  12.        }else{
  13.            for (int i = 0; i < text1.length(); i++) {
  14.                if (text1.charAt(i) == text2.charAt(i)) {
  15.                    s += text1.charAt(i);
  16.                }else{
  17.                    break;
  18.                }
  19.            }
  20.            return s;
  21.        }
  22.    }

Explanation:

Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).  

<em />

Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).

There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).

If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.

The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>

<em />

At the end, return the s as output (Line 21).

5 0
3 years ago
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