Ask question

Ask question

All categories

PilotLPTM [1.2K]

3 years ago

8

Patrick made a scale drawing of a newly planted hotel the height of the scale drawing is 27 inches what would be the actual heig

ht, in meters, of the hotel if it was constructed.
pls hurry lol

2 answers:

Charra [1.4K]3 years ago

7 0

Answer:

0.6858 meters

Step-by-step explanation:

Margaret [11]3 years ago

6 0

The answer is 0.6858

You might be interested in

I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

7 0

3 years ago

1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t

Sophie [7]

$1)\text{ }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

$\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}$ $N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}$

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

$\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}$

So after 70 days, 5.625 mg will be left

4 0

1 year ago

the sum of 3 decimal numbers is 6. Exactly one of the numbers is less than 1 what could those numbers be.

kati45 [8]

There are infinitely many solutions to this problem (which is why it asks what could those numbers be), so you just have to make one up!

Start with the first sentence.
x + y + z = 6.0

Now one of those numbers has to be less than 1. I'll choose x. And I'll choose a random number, say, 0.7.

0.7 + y + z = 6.0

Now I'll subtract 0.7 from both sides to see what y and z have to add up to.

0.7 + y + z - 0.7 = 6.0 - 0.7
y + z = 5.3

Now I'll choose a random number for y that's less than 5.3.

2.6 + z = 5.3

And subtract 2.6 from both sides to find z.

2.6 + z - 2.6 = 5.3 - 2.6
z = 2.7

And now we have our numbers!
x = <u>0.7</u>
y = <u>2.6</u>
z = <u>2.7</u>

3 0

3 years ago

What is the opposite -2/5

Yuri [45]

Answer:

it would be a positive 2/5

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Need help with problem number 6 please

butalik [34]

So to get the sides you need to cube them
(192)^1/3---->5.769
(375)^1/3---->7.21125
7.21125-5.769= 1.44225
3^(1/3)= 1.44225

Answer: A

3 0

3 years ago