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8090 [49]
3 years ago
8

Select the correct answer.

Mathematics
2 answers:
irakobra [83]3 years ago
4 0
24-(6x3)+52-(8)
24-18+52-8
50
Ilia_Sergeevich [38]3 years ago
4 0
Using PEMDAS, you would do the parentheses first.

24-6x3+52-(16/2)
24-6x3+52-(8)

Then you would do the multiplication next

24-18+52-8

Lastly you would do the addition and subtraction

6+52-8
58-6
52

Your answer would be 52


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Find area of blue shaded region
RUDIKE [14]

Answer:

\approx \: 7.33 \:  {cm}^{2}

Step-by-step explanation:

Area of the blue shaded region

=  \frac{ \theta}{360 \degree}  \times \pi r_1^2  - \frac{ \theta}{360 \degree}  \times \pi r_2^2  \\  \\  =   \frac{ \pi\theta}{360 \degree} ( r_1^2 - r_2^2) \\  \\ ( r_1 = 4 \: cm, \:  \:  r_2 = 3\: cm, \:  \:  \theta = 120 \degree) \\  \\ =   \frac{ 3.14 \times 120 \degree}{360 \degree} ( 4^2 - 3^2) \\  \\  =   \frac{ 3.14 }{3}  \times 7 \\  \\  =  \frac{21.98}{3}  \\  \\  = 7.32666667 \\  \\  \approx \: 7.33 \:  {cm}^{2}

8 0
3 years ago
1. What is the cross section formed by cutting a cylinder perpendicular to its base?
tatyana61 [14]

Answer:

1

Depends on the cross section axis

place a cylinder can on a table , circular and side down .Look down at it and you see the other end so the cross section is circle

Turn it on its side and the cross section is rectangle

3 0
3 years ago
Find the coefficient of the 4th term in expansion of (x +2 )^5
LuckyWell [14K]
(x + 2)^5=(x+2)^2\cdot{(x+2)^2}\cdot{(x+2)}\\\\(x+2)^5=(x^2+4x+4)\cdot{(x^2+4x+4)}\cdot(x+2)

(x+2)^5=(x^4+8x^3+24x^2+32x+16)\cdot(x+2)

(x+2)^5=x^5+10x^4+40x^3+80x^2+80x+32

10

6 0
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A farmer planted 32 rows of sweet peppers. Each row had 16 sweet pepper plants. How many plants does he have ALTOGETHER​
Anuta_ua [19.1K]

Answer:

512

Step-by-step explanation:

32*16=512

4 0
2 years ago
Read 2 more answers
g A law firm has six senior and seven junior partners. A committee of three partners is selected at random to represent the firm
expeople1 [14]

Answer:

133/143

Step-by-step explanation:

Let S be the sample space

Let E be the event of selecting three committee partners with at least one junior partner.

Partners in the law firm include:

Senior partners = 6

Junior partners = 7

Total partners = 13

n(S) = number of ways of selecting 3 partners from 13 = 13C3

n(S) = 13C3 = 13!/(10!3!) = (13x12x11)/(3x2x1) = 286

To get n(E) i.e least 1 junior partner in the selected committee, we may have:

(2 senior and 1 junior) or ( 1 senior and 2 junior) or (3 junior).

Therefore, the required number of way is given below:

= (6C2 x 7C1) + (6C1 x 7C2) + 7C3

= [(6x5)/2 x 7] + [6 x (7x6)/2] + [(7x6x5)/(3x2)]

= 105 + 126 + 35

n(E) = 266

Therefore, the probability P(E) that at least one of the junior partners is on the​ committee is given below:

P(E) = n(E) /n(S)

P(E) = 266/286

P(E) = 133/143

5 0
3 years ago
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