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3 years ago

13

Lucky Joe won $32,000,000 in a lottery. Every year for 10 years he spent 50% of what was left. How much did Lucky Joe have after

10 years?

1 answer:

aniked [119]3 years ago

8 0

Answer:

31,250

Step-by-step explanation:

32,000,000x0.5= 16,000,000

repeat the process 10 times and you've got 31,250

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What is the degree of this polynomial? x ^ 3 + xy + x * y ^ 2 + 5y + 3

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Answer:

The degree of the given polynomial is 3.

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Write all the names of the quadrilateral shown.<br> ???

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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

so

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

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3 years ago

Quadrilateral EFGH was dilated by a scale factor of 2 from the center (1, 0) to create E'F'G'H'. Which characteristic of dilatio

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The answer choice which is the characteristic of dilations comparing both segments is; A segment in the image is proportionally longer or shorter than its corresponding segment in the pre-image

<h3>Which answer choice compares segment E'F' to segment EF?</h3>

By consider the coordinates of the quadrilaterals EFGH and E'F'G'H' as given in the task content image, it follows that the coordinates are as follows;

E(0, 1), F(1, 1), G(2, 0), and H(0, 0)

E'(-1, 2), F'(1, 2), G'(3, 0), and H'(-1, 0)

Upon computation of the length of the segments, it follows that the two segments are in proportions. Hence, the answer choice which is correct is; A segment in the image is proportionally longer or shorter than its corresponding segment in the pre-image.

Remark:

A segment that passes through the center of dilation in the pre-image continues to pass through the center of dilation in the image.
A segment in the image has the same length as its corresponding segment in the pre-image.
A segment that passes through the center of dilation in the pre-image does not pass through the center of dilation in the image.
A segment in the image is proportionally longer or shorter than its corresponding segment in the pre-image.

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