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3 years ago

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Lucky Joe won $32,000,000 in a lottery. Every year for 10 years he spent 50% of what was left. How much did Lucky Joe have after

10 years?

1 answer:

aniked [119]3 years ago

8 0

Answer:

31,250

Step-by-step explanation:

32,000,000x0.5= 16,000,000

repeat the process 10 times and you've got 31,250

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3 years ago

HELP PLEASE. URGENT TIMED QUIZ.

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Answer: a

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2 years ago

Which is the graph of a logarithmic function?

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Answer:

Answer is the first choice.

Step-by-step explanation:

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2 years ago

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Find z if X=27, μ=20, and α=3.4. Round to the nearest hundredth if necessary.

Scrat [10]

Answer:

A. $Z=2.06$

Step-by-step explanation:

We want to find the Z-score of $X=27$ if the population mean is $\mu=20$ ,and the population standard deviation is $\sigma=3.4$ .

We use the formula:

$Z=\frac{X-\mu}{\sigma}$

We substitute the values to obtain:

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The correct answer is A.

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3 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

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3 years ago