Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
15
Step-by-step explanation:
Answer: D
Step-by-step explanation: By using SOH for sin A, 'S' being sin, 'O' being opposite side of angle A and 'H' being the hypotenuse which is the longest part of the triangle you would find that 15 is opposite from Sin A and 17 the hypotenuse, 15/17.
For cos A you would use CAH, C= cos, A which is the adjacent of the triangle located next to angel A which is 8, and H= hypotenuse (also note that the hypotenuse never changes even if the angle may be different) CAH would be cos A = 8/17
Answer:
24
Step-by-step explanation:
-27 - x = -51
+27 +27
-x = -24
x = 24
I assume you're asking where it meets the y axis
In an equation the last number is the y intercept so I'm this case it would be 1
