This is abt triangles

1. through (0,-1) slope= -1

nasty-shy [4]

Answer:

Step-by-step explanation:

I will give you equations in slope intercept form

1.

y=-x-1

2.

y= -2x - 6

4 0

3 years ago

The radius of a cylindrical water tank is 6.5 ft, and its height is 19 ft. What is the volume of the tank?

creativ13 [48]

Answer:

The volume of the cylinder is 2520.64ft³

Step-by-step explanation:

To calculate the volume of a cylinder we have to use the following formula:

v = volume

h = height = 19ft

π = 3.14

r = radius = 6.5ft

v = (π * r²) * h

we replace with the known values

v = (3.14 * (6.5ft )²) * 19ft

v = (3.14 * 42.25ft²) * 19ft

v = 132.665ft² * 19ft

v = 2520.64ft³

The volume of the cylinder is 2520.64ft³

4 0

3 years ago

What is the y1 of 3x-5y=20

Aliun [14]

Unsure of what you mean by "y1."

If you wish to solve this eqn for y, do this:
-5y = - 3x + 20,
-3x + 20
y = ---------------- = (3/5)x - 4 (answer)
-5

5 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

Using the completing-the-square method, rewrite f(x) = x2 + 10x + 7 in vertex form

mr Goodwill [35]

Answer:

f(x) = (x - (-5))^2 + (-18)

Step-by-step explanation:

Given:

f(x) = x^2 + 10x + 7

Rewrite f(x) in vertex form

Solution:

f(x) = ax^2 + bx + c is a quadratic function.

The vertex form of f(x) is a(x - h)^2 + k, where (h, k) is the vertex.

=> f(x) = x^2 + 10x + 7

= x^2 + 10x + 25 - 18

= (x + 5)^ - 18

= (x - (-5))^2 + (-18)

=> f(x) can be rewritten in form of a(x - h)^2 + k, where (h, k) is the vertex, with a = 1, h = -5, k = -18

6 0

3 years ago