36 equally-likely outcome: (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1),(6,2), (6,3), (6,4), (6,5), (6,6)
Solution:
Outcomes with first number being old number and second being even number: (1,2), (1,4), (1,6), (3,2), (3,4), (3,6), (5,2), (5,4), (5,6) = 9 outcomes
P(old,even) = 9/36 =1/4 = 0.25
Answer:
x = 13 and x = 1
Step-by-step explanation:
(x-7)² = 36
simplify left side of equation
x² - 14x + 49 = 36
Our object now is to get every thing on the left side of the equal sign so we can factor. To do this, we subtract 36 from both sides
x² - 14x + 13 = 0
we then factor the left side of the equation
( x - 1 ) ( x - 13 ) = 0
we then set factors equal to 0 and solve both factors for x
x - 1 = 0
add 1 to both sides
x = 1
x - 13 = 0
add 13 to both sides
x = 13
The values of x are x = 13 and x = 1
