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2 years ago

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The length of a human pregnancy is normally distributed with a mean of 270 days with a standard deviation of 8 days. How many da

ys would a pregnancy last for the shortest 15%? Round answer to 2 decimal places. Answer

1 answer:

solniwko [45]2 years ago

6 0

Answer:

261.71

Step-by-step explanation:

The calculation of days is shown below:-

$X = \mu + Z\sigma$

where,

Mean = 270

standard deviation is 8

And, the normsinv is -1.036

Now placing these values to the above formula

So, the number of days is

= 270 + (-1.036433389) × 8

= 270 + (-8.29146711)

= 261.708533

or

= 261.71

Therefore for computing the number of days we simply applied the above formula and for (-1.036433389) please find in the attachment.

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Use the Euclidean Algorithm to compute the greatest common divisors indicated. (a) gcd(20, 12) (b) gcd(100, 36) (c) gcd(207, 496

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Answer:

(a) $gcd(20, 12)=4$

(b) $gcd(100, 36)=4$

(c) $gcd(496,207 )=1$

Step-by-step explanation:

The Euclidean algorithm is an efficient method for computing the greatest common divisor of two integers, without explicitly factoring the two integers.

The Euclidean algorithm solves the problem:

<em> Given integers </em> $a, b$ <em>, find </em> $d=gcd(a,b)$ <em />

Here is an outline of the steps:

Let $a=x$ , $b=y$ .
Given $x, y$ , use the division algorithm to write $x=yq+r$ .
If $r=0$ , stop and output $y$ ; this is the gcd of $a, b$ .
If $r\neq 0$ , replace $(x,y)$ by $(y,r)$ . Go to step 2.

The division algorithm is an algorithm in which given 2 integers N and D, it computes their quotient Q and remainder R.

Let's say we have to divide N (dividend) by D (divisor). We will take the following steps:

Step 1: Subtract D from N repeatedly.

Step 2: The resulting number is known as the remainder R, and the number of times that D is subtracted is called the quotient Q.

(a) To find $gcd(20, 12)$ we apply the Euclidean algorithm:

$20 = 12\cdot 1 + 8\\ 12 = 8\cdot 1 + 4\\ 8 = 4\cdot 2 + 0$

The process stops since we reached 0, and we obtain $gcd(20, 12)=4$ .

(b) To find $gcd(100, 36)$ we apply the Euclidean algorithm:

$100 = 36\cdot 2 + 28\\ 36 = 28\cdot1 + 8\\ 28 = 8\cdot 3 + 4\\ 8 = 4\cdot 2 + 0$

The process stops since we reached 0, and we obtain $gcd(100, 36)=4$ .

(c) To find $gcd(496,207 )$ we apply the Euclidean algorithm:

$496 = 207\cdot 2 + 82\\ 207 = 82\cdot 2 + 43\\ 82 = 43\cdot 1 + 39\\ 43 = 39\cdot 1 + 4\\ 39 = 4\cdot 9 + 3\\ 4 = 3\cdot 1 + 1\\ 3 = 1\cdot 3 + 0$

The process stops since we reached 0, and we obtain $gcd(496,207 )=1$ .

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