Solve the right triangle. State the side lengths to the nearest tenth and the angle measures to the nearest degree.

Mathematics

2 answers:

Elden [556K]4 years ago

8 0

Answer:

Option B

Step-by-step explanation:

The two acute angles of a right triangle are equal.

$\angle \: A + 18 = 180$

$\angle \: A= 90 - 18 = 72 \degree$

Recall the mnemonics SOH-CAH-TOA

The tangent ratio is opposite over adjacent.

$\tan(18) = \frac{AC}{21}$

$AC = 21 \tan(18)$

$AC = 6.8$

The sine ratio is opposite over hypotenuse

Using the sine ratio,

$\sin(72) = \frac{21}{AB}$

$AB = \frac{21}{ \sin(72) } = 22.1$

Eva8 [605]4 years ago

8 0

Answer:

it 55

Step-by-step explanation:

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Determine the IQR of this data then indicate whether the data set contains any outliers . Explain how you determined this

slega [8]

Place the values in ascending order first:

4, 10, 10, 11, 12, 12, 12, 12, 13, 13, 15, 15, 17, 18, 19, 20

There are 16 values

IQR is 3/4th term - 1/4th term

The 12th value is 15 while the 4th value is 11

Therefore IQR = 15-11 which is 4

I would say the outlier is 4.

Justification: Figure out the mean with the value of 4 then discount it to see whether the mean is affected by the outlier.

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3 years ago

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lara [203]

Answer:

False

Step-by-step explanation: