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Lerok [7]
3 years ago
15

What is the volume of this sphere

Mathematics
2 answers:
ruslelena [56]3 years ago
8 0

Answer:

3052.08 m³

Step-by-step explanation:

\boxed{volume \: of \: sphere =  \frac{4}{3}\pi {r}^{3}  }

Given that the radius is 9m, r=9.

Volume of sphere

=  \frac{4}{3} (3.14)(9^{3} )

= 3052.08 m³

navik [9.2K]3 years ago
8 0

Answer:

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

Volume = 4/3 • π • r³

Volume = 4/3 • 3.14 • (9)³

Volume = 4/3 • 3.14 • 9 • 9 • 9

Volume = 4 • 3.14 • 27 • 9

Volume = 3052.08 cm³

\\

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1. 3(6a); for a=3<br>2. 5d(4); for d=-2​
Firdavs [7]

Answer:

Step-by-step explanation:

1. Solution for 3(6a)a=3 equation:

Simplifying

3(6a) * a = 3

Remove parenthesis around (6a)

3 * 6a * a = 3

Multiply 3 * 6

18a * a = 3

Multiply a * a

18a2 = 3

Solving

18a2 = 3

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '18'.

a2 = 0.1666666667

Simplifying

a2 = 0.1666666667

Take the square root of each side:

a = {-0.408248291, 0.408248291}

2.Solution for 5d(4)d=-2 equation:

Simplifying

5d(4) * d = -2

Reorder the terms for easier multiplication:

5 * 4d * d = -2

Multiply 5 * 4

20d * d = -2

Multiply d * d

20d2 = -2

Solving

20d2 = -2

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '20'.

d2 = -0.1

Simplifying

d2 = -0.1

Reorder the terms:

0.1 + d2 = -0.1 + 0.1

Combine like terms: -0.1 + 0.1 = 0.0

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5 0
3 years ago
On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

4 0
4 years ago
Is that the only ones I used
jek_recluse [69]

Answer:

yes

Step-by-step explanation:

7 0
3 years ago
Find the area of the shaded sector. Leave your answer in terms of π.
bearhunter [10]

Answer:

d=10m

r=10/2=5m

The Area is:

(πr^{2}) /2

(π5^2) / 2

=25π/2

=12.5π

8 0
3 years ago
Read 2 more answers
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Zina [86]
There are several different angles associated with circles. Perhaps the one that most immediately comes to mind is the central angle. It is the central angle's ability to sweep through an arc of 360 degrees that determines the number of degrees usually thought of as being contained by a circle.
4 0
3 years ago
Read 2 more answers
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