G(x)=(1/x+2) and h(x)=3x domain of g o h
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Check the picture below.
now, an angle bisector I assume, since it intersects the opposite segment at D and then at E. An angle bisector cuts an angle in two equal halves, so if ∡CAB is 82°, that just means that ∡CAE is one of those halves, or 41°.
now, an angle bisector I assume, since it intersects the opposite segment at D and then at E. An angle bisector cuts an angle in two equal halves, so if ∡CAB is 82°, that just means that ∡CAE is one of those halves, or 41°.
I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set 
for this example.)
The length of each cross section (the side lying in the base) has length determined by the horizontal distance
between the y-axis 
and the curve 
. In terms of 
, this distance is 
. The height of each cross section is twice the value of , so the area of each rectangular cross section should be 
.
This means the volume would be given by the integral
The length of each cross section (the side lying in the base) has length determined by the horizontal distance
This means the volume would be given by the integral