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3 years ago

Find the sum

Mathematics

2 answers:

mafiozo [28]3 years ago

4 0

the answer is:

-5w - 12

skelet666 [1.2K]3 years ago

3 0

The answer should be
-5w-12

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What are the coordinates of the centroid of a triangle with vertices A(−3, 1) , B(1, 6) , and C(5, 2) ? Enter your answer in the

kirza4 [7]

<u>ANSWER</u>: The centroid is (1,3)

<u>Explanation:</u>

The centroid is the intersection of the medians of the triangle.

So we need to find the equation of any two of the medians and solve simultaneously.

Since the median is the straight line from one vertex to the midpoint of the opposite side, we find the midpoint of any two sides.

We find the midpoint of AC using the formula;

$N=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

$N=(\frac{-3+5}{2}, \frac{1+2}{2})$

$N=(\frac{2}{2}, \frac{3}{2})$

$N=(1, \frac{3}{2})$

The equation of the median passes through $B(1,6)$ and $N=(1, \frac{3}{2})$ .

This line is parallel to the y-axis hence has equation

$x=1$ -------first median.

We also find the midpoint M of BC.

$M=(\frac{1+5}{2}, \frac{6+2}{2})$

$M=(\frac{6}{2}, \frac{8}{2})$

$M=(3, 4)$

The slope of the median, AM is

$Slope_{AM}=\frac{4-1}{3--3}$

$Slope_{AM}=\frac{3}{6}$

$Slope_{AM}=\frac{1}{2}$

The equation of the median AM is given by;

$y-y_1=m(x-x_1)$

We use the point M and the slope of AM.

$y-4=\frac{1}{2}(x-3)$

$2y-8=(x-3)$

$2y-x=-3+8$

$2y-x=5$ -------Second median

We now solve the equation of the two medians simultaneously by putting $x=1$ in to the equation of the second median.

$2y-1=5$

$2y=5+1$

$2y=6$

$y=3$

Hence the centroid has coordinates $(1,3)$

7 0

3 years ago

Read 2 more answers

The Bungling Brothers Circus is in town and you are part of the crew that

Kipish [7]

Answer:

a. 80.83 ft b. 40.42 ft

Step-by-step explanation:

Let h = height of pole = 70 ft, L = length of cable and x = distance of cable on ground to pole and Ф = angle between cable and ground.

a) How long is the cable?

Since L, h and x form a right-angled triangle with angle Ф and h being the opposite side to Ф and L being the hypotenuse side, by trigonometric ratios,

sinФ = h/L

L = h/sinФ

L = 70 ft/sin60°

L = 70 ft/0.8660

L = 80.83 ft

b) How far from the pole should the cable be attached to the ground?

Since L, h and x form a right-angled triangle with angle Ф and h being the opposite side to Ф and x being the adjacent side, by trigonometric ratios,

tanФ = h/x

x = h/tanФ

x = 70 ft/tan60°

x = 70 ft/1.7321

x = 40.42 ft

8 0

2 years ago