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3 years ago

Find the sum

Mathematics

2 answers:

mafiozo [28]3 years ago

4 0

the answer is:

-5w - 12

skelet666 [1.2K]3 years ago

3 0

The answer should be
-5w-12

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I need help pls pls pls pls

svetoff [14.1K]

Answer:

1. -18x+6

multiply everything inside with the number outside the bracket

2. -18x-6

same as number one

3. 18x-12

same as number one

4. -18x-6

same as number one

for 5 I can't see it well but it should be similar

you just need to substitute what's outside the bracket to what Is inside the bracket

6 0

2 years ago

Read 2 more answers

Which statement is not correct?

Pachacha [2.7K]

Answer:

b.) because it is over 90*

Step-by-step explanation:

8 0

2 years ago

the produce department of a grocery store sold 288 pounds of tomatoes. the weight represented 72% of the shipment the store rece

Shtirlitz [24]

207.4 pounds originally was received

3 0

3 years ago

Which shows a correct order to solve this story problem?

Nesterboy [21]

Answer is C

3.2 oz + 4.7oz = 7.9 oz * 4 = 31.6oz total

6 0

3 years ago

how to integrate <img src="https://tex.z-dn.net/?f=e%5E%7B2s%7D%20%2ACos%20%5Cfrac%7Bs%7D%7B4%7D" id="TexFormula1" title="e^{2s}

icang [17]

Answer:

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Step-by-step explanation:

Step(i):-

Given that $f(s) = e^{2s} cos\frac{s}{4}$

Now integrating

$\int\limits {f(s)} \, ds = \int\limits {e^{2s} cos\frac{s}{4} ds$

By using integration formula

$\int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2} } ( a cos b x + b sin b x )$

Step(ii):-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2} } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Final answer:-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

6 0

2 years ago