4.16 I think if I did the math right
Answer:
should be left in the candy bar.
Step-by-step explanation:
Jenn and David shared a candy bar. Let's assume the bar was split into 10 parts, since 10 is the denominator of the fraction.
First, we need to add how much that the candy bar was eaten so we can subtract easier.
Jenn ate three tenths.
David ate four tenths.
So, seven tenths of the candy bar was eaten. We need to subtract that from a whole, because we need to know how much candy is left.
So, there are 3/10, or 0.3, of the candy bar left to share later.
Answer:
A) $204 B) $331.50
Step-by-step explanation:
For both scenarios, you just multiply the amount of hours worked by the amount per hour to find the total amount made.
A monomial has one term. Therefore, A is the only one with one term.
Answer:
Step-by-step explanation:
From the given information,
Suppose
X represents the Desktop computer
Y represents the DVD Player
Z represents the Two Cars
Given that:
n(X)=275
n(Y)=455
n(Z)=405
n(XUY)=145
n(YUZ)=195
n(XUZ)=110
n((XUYUZ))=265
n(X ∩ Y ∩ Z) = 1000-265
n(X ∩ Y ∩ Z) = 735
n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)
145 = 275+455 - n(X ∩ Y)
n(X ∩ Y) = 585
n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)
195 = 455+405-n(Y ∩ Z)
n(Y ∩ Z) = 665
n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)
110 = 275+405-n(X ∩ Z)
n(X ∩ Z) = 570
a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)
n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735
n(X ∪ Y ∪ Z) = 50
c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)
n(X ∪ Y ∪ C') = 145-50
n(X ∪ Y ∪ C') = 95
