Question

Please help as soon as possible

Answer 1

To solve this problem you must apply the proccedure shown below:

You must switch the variables, and then, you must solve for $y$, as following:

$x=-\frac{1}{2} \sqrt{y} +3\\ (x-3)^{2} = (\frac{1}{2}\sqrt{y})^{2} \\ y=4x^{2} -24x+36\\ f^{-1} (x)=4x^{2} -24x+36$

Therefore, as you can see, the answer is: $f^{-1} (x)= 4x^{2} -24x+36$