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dlinn [17]
3 years ago
11

Each base of a triangular prism is a right triangle with side lengths 3 inches, 4 inches, and 5 inches. The height of the prism

is 7 inches. What is the surface area?
Mathematics
1 answer:
Gnom [1K]3 years ago
6 0
<span>Area of the base = 3*4 / 2 = 6
</span><span>Area of BOTH bases = 12 sq inches
Area of one face = 3 * 7 = 21 sq inches
</span>Area of 2nd face = 4 * 7 = 28 <span>sq inches
</span>Area of 3rd face =  5 * 7 = 35 <span>sq inches

TOTAL Area = 96 </span><span>sq inches</span>

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What is the justification for each step in solving the inequality?
Fed [463]

Step-by-step explanation:

3x+\frac{5}{8}\geq 4x-\frac{1}{2}

Subtract 5/8 on both sides

To subtract 5/8 we make the denominators same

3x\geq 4x-\frac{1*4}{2*4}-\frac{5}{8}

Addition or Subtraction property of order is used

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Subtract 4x on both sides

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5 0
3 years ago
The sets of numbers 3, 4, 5 and 8, 15, 17 are Pythagorean triples. Use what you know about the Pythagorean Theorem and explain o
konstantin123 [22]

Answer:

When we have 3 numbers, like:

a, b and c.

Such that:

a < b < c.

These numbers are a Pythagorean triplet if the sum of the squares of the two smaller numbers, is equal to the square of the larger number:

a^2 + b^2 = c^2

This is equivalent to the Pythagorean Theorem, where the sum of the squares of the cathetus is equal to the hypotenuse squared.

Now that we know this, we can check if the given sets are Pythagorean triples.

1)  3, 4, 5

Here we must have that:

3^2 + 4^2 = 5^2

solving the left side we get:

3^2 + 4^2 = 9 + 16 = 25

and the right side:

5^2 = 25

Then we have the same in both sides, this means that these are Pythagorean triples.

2) 8, 15, 17

We must have that:

8^2 + 15^2 = 17^2

Solving the left side we have:

8^2 + 15^2 = 64 + 225 = 289

And in the right side we have:

17^2 = 17*17 = 289

So again, we have the same result in both sides, which means that these numbers are Pythagorean triples

4 0
2 years ago
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