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Paul [167]
3 years ago
7

The supplement of an angle measures 102°. what is the measurement of the angle?

Mathematics
1 answer:
Evgen [1.6K]3 years ago
3 0
   
180° - 102° = 78°
Correct answer:   a.  



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Solve the following linear system by graphing <br> 4x+5y=10<br> 3x-3y=21
Inga [223]

Answer:

y = 2

x = 5

Step-by-step explanation:

4x + 5y = 10 | ×3 |

3x - 3y = 21 | ×4 |

12x + 15y = 30

12x - 12y = 84

____________--

27y = -54

y = -54/27

y = 2

4x + 5y = 10 | ×3 |

3x - 3y = 21 | ×5 |

12x + 15y = 30

15x - 15y = 105

____________+

27x = 135

x = 135/27

x = 5

6 0
3 years ago
24. What are the x and y intercepts of the following
Mila [183]

Answer:

C

A. X-intercept (6,0) and y-intercept (0,-8) wrong

B. x-intercept (-8,0) and y-intercept (0,6)wrong

C. x-intercept (4,0) and y-intercept (0,-3) correct

D. x-intercept (-3,0) and y-intercept (0,4) wrong

3 0
2 years ago
The price has changed from 125$ to 75$. By how much percent did it change
Firlakuza [10]

Answer:

-40 %

Step-by-step explanation:

((y2 - y1) / y1)*100 = your percentage change

(where y1=start value and y2=end value)

((75 - 125) / 125) * 100 = -40 %

The percentage change from 125 to 75 is -40 %

6 0
2 years ago
Read 2 more answers
A plane intersects one nappe of a double-napped cone such that the plane is not perpendicular to the axis and is not parallel to
meriva
Ellipse is the correct answer
6 0
3 years ago
Read 2 more answers
How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
2 years ago
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