Multiply the original DE by xy:
xy2(1+x2y4+1−−−−−−−√)dx+2x2ydy=0(1)
Let v=xy2, so that dv=y2dx+2xydy. Then (1) becomes
x(y2dx+2xydy)+xy2x2y4+1−−−−−−−√dxxdv+vv2+1−−−−−√dx=0=0
This final equation is easily recognized as separable:
dxxln|x|+CKxvKx2y2−1K2x4y4−2Kx2y2y2=−dvvv2+1−−−−−√=ln∣∣∣v2+1−−−−−√+1v∣∣∣=v2+1−−−−−√+1=x2y4+1−−−−−−−√=x2y4=2KK2x2−1integrate both sides
Answer:
the sum of 2 consecutive even integers is 66.
Step-by-step explanation:
This means that if one integers is x, the other must be either x-2 or x+2. Therefore, we can write 6=x+(×-2)=2×2. Solving for x, we can find ×=34. this means that the other integer is 34-2=32. indeed, 32+34=66, and done hope this helped C:
Answer:
Step-by-step explanation:
