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4 years ago

5

Lines m and n are parallel. Which of the other 5 named angles have a measure of 110°?

1 answer:

Cloud [144]4 years ago

4 0

Answer:

2 and angle that is left of 5

Step-by-step explanation:

Angle 2 is vertical from 110, and vertical angles are congruent. From this, we can figure out that 2 and 3 (they're supplementary) are 70. Angles 5 and 3 are Alternate Interior Angles, and therefore must be congruent. The one to the left of 5 is supplementary to it, and therefore must be 110. Your answers are angle 2 and the angle that is left of 5.

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The end of a house has the shape of a square surmounted by an equilateral triangle. If the length of the base is measured to be

sergij07 [2.7K]

Answer:

The area of the end is 1755.44 ft²

Therefore, the maximum error in calculating area of the end is 8.3592

Step-by-step explanation:

Consider the provided information.

The length of the base is measured to be 35 feet, with a maximum error in measurement of 1 inch,

$1\ inch = \frac{1}{12}\ feet$

The area of shape = Area of square + Area of equilateral triangle

$A=x^2+\frac{\sqrt{3}}{4}x^2$

Substitute x=35 in above.

$A=(35)^2+\frac{\sqrt{3}}{2}\times (35)^2=1755.44$

Hence, the area of the end is 1755.44 ft²

Differentiate $A=x^2(1+\frac{\sqrt{3}}{4})$ with respect to x as shown:

$dA=2x\ dx(1+\frac{\sqrt{3}}{4})$

Substitute dx =1/12 and x=35

$dA=2(35)\ \frac{1}{12}(1+\frac{\sqrt{3}}{4})=8.3592$

Therefore, the maximum error in calculating area of the end is 8.3592

6 0

3 years ago

What number is bigger -2 or -5 or -1

V125BC [204]

Hi , the answer is -1 , because -1 is the number that is closest to zero.

6 0

3 years ago

Read 2 more answers

Giving brailiest for free so what's 10/5

Korvikt [17]

Hey there!

10/5

= 10 ÷ 5

= 2

Let’s check to see if your answer is accurate:

5 + 5

= 2 + 2 + 2 + 2 + 2

= 4 + 4 + 2

= 8 + 2

= 10

Thus, 10 ÷ 5 does equal 2

Therefore, your answer is: 2

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

6 0

2 years ago

An equation of an ellipse is given. y2 = 1 − 3x2 (a) Find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = (

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given

$y^2=1-3x^2$

$3x^2+y^2=1$

$\frac{x^2}{(\frac{1}{\sqrt{3}})^2}+\frac{y^2}{1}=1$

therefore it is a vertical ellipse

thus a=1

$b=\frac{1}{\sqrt{3}}$

eccentricity of Ellipse

$e^2=1-\frac{b^2}{a^2}$

$e^2=1-\frac{1}{(\sqrt{3})^2}$

$e^2=1-\frac{1}{3}$

$e^2=\frac{2}{3}$

$e=\sqrt{\frac{2}{3}}$

Focii are $(0,ae)$ and $(0,-ae)$

$ae=1\times \sqrt{\frac{2}{3}}$

thus focii are $(0,\sqrt{\frac{2}{3}})$ & $(0,-\sqrt{\frac{2}{3}})$

(b) Length of major axis $=2a=2\times 1$

length of minor axis $=2b=2\times \sqrt{\frac{2}{3}}=2\cdot \sqrt{\frac{2}{3}}$

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3 years ago

Which pair of number dose 13 is it 4 and 5 is it 3 and 4 is it 2 and 3 or 3 and 5

tester [92]

Wait what are you asking?

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3 years ago