All categories

4 years ago

Rewrite the equation 4 x^2– 3x + 9 = 2x + 1 in standard form.

Mathematics

1 answer:

snow_tiger [21]4 years ago

7 0

Answer:

this is quadratic equation

ax^2+bx+c=0

Step-by-step explanation:

4x^2-5x+8=0

You might be interested in

What is the coefficient of the term of degree 2 in the polynomial below?

Vanyuwa [196]

D i believe is the answer

3 0

4 years ago

If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t − 16t2. Fi

horrorfan [7]

I'm pretty sure its 10

5 0

4 years ago

Read 2 more answers

Elevator 1 in an office building moved from ground position to a final position of +12 feet. Elevator 2 in the same building mov

NikAS [45]

Elevator 1 is 12 ft above ground level...and elevator 2 is 15 ft below ground level

8 0

3 years ago

Read 2 more answers

A particle moves along the curve below. y = √ 8 + x 3 As it reaches the point ( 1 , 3 ) , the y -coordinate is increasing at a r

Dmitry [639]

Answer:

<em>The x-coordinate is changing at 10 cm/s</em>

Step-by-step explanation:

<u>Rate of Change</u>

Suppose two variables x and y are related by a given function y=f(x). If they both change with respect to a third variable (time, for instance), the rate of change of them is computed as the derivative using the chain rule:

$\displaystyle \frac{dy}{dt}=\frac{dy}{dx}\cdot \frac{dx}{dt}$

We have

$y=\sqrt{8+x^3}$

Or, equivalently

$y^2=8+x^3$

We need to know the rate of change of x respect to t. We'll use implicit differentiation:

$\displaystyle 2y\cdot \frac{dy}{dt}=3x^2\cdot \frac{dx}{dt}$

Solving for dx/dt

$\displaystyle \frac{dx}{dt}=\frac{2y\cdot \frac{dy}{dt}}{3x^2}$

Plugging in the values x=1, y=3, dy/dt=5

$\displaystyle \frac{dx}{dt}=\frac{2(3)\cdot 5}{3\cdot 1^2}=10$

The x-coordinate is changing at 10 cm/s

7 0

3 years ago

(A) find F(x) for the indicated values of x, if possible

dem82 [27]

Answer:

A) The indicated values of F(x) for x=-3 and x=5 are $F(-3)=-27$ and $F(5)=125$

B) The domain of f is the set of all real numbers

Step-by-step explanation:

Given that the function F is defined by

$F(x)=x^3$ for x=-3,5

A) To find F(x) for the indicated values of x :

Given $F(x)=x^3$ for x=-3,5

Put x=-3 in the given function

$F(-3)=(-3)^3$

$=(-3)\times (-3)\times (-3)$

$=-27$

Therefore $F(-3)=-27$

Put x=5 in the given function

$F(5)=(5)^3$

$=(5)\times (5)\times (5)$

$=125$

Therefore $F(5)=125$

The indicated values of F(x) for x=-3 and x=5 are $F(-3)=-27$ and $F(5)=125$

B) To find the domain of f :

The domain of the f in the given expression is the set of all real numbers except where the expression $x^3$ is undefined. In this case, there is no real number that makes the expression undefined.

The domain of f is the set of all real numbers

8 0

3 years ago