Rewrite the equation 4 x^2– 3x + 9 = 2x + 1 in standard form.
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Answer:
The range is the resulting y-values we get after substituting all the possible x-values.
For the given function :
<u>See the attached figure.</u>
The zeros of the denominator at x = 0
The domain is: (-∞,0)∪(0,∞)
<u>The range</u> of the function is the domain of the inverse function of f(x)
y = 3/(4x) - 4
y + 4 = 3/(4x)
4x = 3/(y+4)
The zeros of the inverse function:
4(y+4) = 0
y + 4 = 0
y = -4
∴ The range is (-∞,-4)∪(-4,∞)
So, the answer is {y | y > –4} ∪ {y | y < – 4}
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<u>Note</u>: If the given function is :
It will be first degree polynomial function.
Both of the domain and the range = all real numbers R
