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garik1379 [7]
4 years ago
6

At the movies, children's tickets are $6 each and adult's tickets are $10 each.

Mathematics
1 answer:
Vilka [71]4 years ago
8 0

Answer:

a + c = 14

14(Pa+Pc) = 10a + 6c

224 = 10a + 6c

Step-by-step explanation:

Price of Children's tickets = $6

Price of Adult's tickets = $10

Shandra buys 14 tickets

Let

Number of adults going to the movie = a

Number of children going to the movie = c

Total price shandra pays = PaQa + PcQc

Where,

Pa = price of adult's tickets

Qa = Quantity of adult's tickets

Pc = Price of children's tickets

Qc = Quantity of children's tickets

Total price = 14(Pa+Pc), that is

a + c = 14

14(Pa+Pc) = 10a + 6c

14(10 + 6) = 10a + 6c

140 + 84 = 10a + 6c

224 = 10a + 6c

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Step-by-step explanation:

The standard form for a quadratic equation in the US has the terms in decreasing order by power on the left of the equal sign, and the right side zero. Preferably, the leading coefficient is positive. This might also be called "general form." Elsewhere, the "standard form" may be different.

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Betty's bakery bakes white bread and brown bread. The loaves of bread are then stored in a store room that can house only 900 lo
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What is 2/15 closest to 0, 1/2, 2
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0 < 2/15 < 1/2 < 2

Each number is decimal form:
0 = 0.00
2/15 = 0.13(repeating 3)
1/2 = 0.50
2 = 2.00

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0.13 - 0 = 0.13
0.50 - 0.13 = 0.37


2/15 is closer to 0.
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Andy's family drove 3 kilometers to the grocery store. how many meters did they drive?
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6 0
3 years ago
Read 2 more answers
Use the quadratic regression to find the equation for the parabola going through these 3 points (-5, 161) (-2, 29) (6, 205)
Rama09 [41]

Answer:

The equation of the parabola is y = 6x^{2}-2b+1

Step-by-step explanation:

First we write a quadratic equation of parabola as y = ax^{2}+bx+c

Now it is given in the question that parabola passes through three points (-5,161),(-2,29),(6,205).

To find the equation we have to get the value of a,b & c.

Now we form three equations to find the value of a,b,c.

We put the value (-5,161) in the equation

161 = a×25+b×(-5)+c

161 = 25a-5b+c----------(1)

Now we put (-2,29) in the equation

29 = a×4+b×(-2)+c

29 = 4a-2b+c---------(2)

Again we put (6,205) in the equation

205 = a×36+6b+c------------(3)

Now we subtract equation (1) from (2)

161-29 = 25a-4a-5b-(-2b)+c-c

132 = 21a-5b+2b

132 = 21a-3b

132 = 3(7a-b)

44 = 7a-b---------(4)

Now we subtract equation (2) from (3)

205-29 = 36a-4a+6b-(-2b)+c-c

176 = 32a+6b+2b

176 = 32a+8b

176 = 8(4a+b)

22 = 4a+b------------(5)

Now we add equation (5) and (4)

44+22 = 7a+4a-b+b

66 = 11a

a = 6

Now we put the value a in equation (4)

44 = 7×6-b

44 = 42-b

44-42 = -b

2 = (-b)

b = (-2)

Now we put the value of a and b in equation number (2)

29 = 4×6-2(-2)+c

29 = 24+4+c

29 = 28+c

c = 29-28

c =1

Finally we put the value of a,b,c in the quadratic equation

y = 6x^{2}+(-2)x+1

y = 6x^{2}-2+1

This is the final answer.

6 0
3 years ago
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