Answer:
The Coordinate of the vertices of Parallelogram RSTU are R(0,0), S(2,3),T(6,3) and U (4,0).
we have to find the vertices of a point which cuts the side of parallelogram ST .It is given that line y = x passes through R.
Suppose that it cuts the side ST at M (p,q).
Equation of line passing through T(6,3)and S (2,3) is
it passes through (p,q)∴
∴ q -3 =0 ...........(1)
Line y=x passes through (p,q).
p -q=0
p=q
Equation (1) becomes
p= q=3
So the line y =x cuts TU at M (3,3).
Answer:
Sixty-three percent is the statistic and 39% is the parameter.
Step-by-step explanation:
Step-by-step explanation:
=(-2)2+8(-2)+18(-2)+12
=4-16-36+12
=4+52+12
=56+12
=68
OR
=4-16-36+12
= -12-24
= -36
X+5<9 subtract 5 from both sides
x<4
The graph will be an area that extends infinitely up, down, and to the left of the vertical line x=4, not including the line itself.
Pythagorean theorem: a2 + b2 = c2
(5)^2 + b2 = (6)^2
25 + b2 = 36
-25. -25
b2 = 11
square root both sides to cancel out
and then label the missing side on the triangle = √11
and then point to the theta symbol and find sin, cos, tan, csc, sec, and cot
for example: sin (opposite/hypotenuse) = √11 /6
SOHCAHTOH
