99 years old due to multiplying 9 x 11
Answer:
There is a 54.328% probability that the next person will purchase no more than one costume.
Step-by-step explanation:
Since in a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance, and Olivia sets up a website where players can buy and sell these costumes online, and information about the number of people who visited. the website and the number of costumes purchased in a single day states that 144 visitors purchased no costume, 182 visitors purchased exactly one costume, and 9 visitors purchased more than one costume, to determine, based on these results, the probability that the next person will purchase no more than one costume as a decimal to the nearest hundredth, the following calculation must be performed:
144 + 182 + 9 = 335
335 = 100
182 = X
182 x 100/335 = X
18,200 / 335 = X
54,328 = X
Therefore, there is a 54.328% probability that the next person will purchase no more than one costume.
Answer: the length of each of the two equal sides is 25 centimeters
Step-by-step explanation:
Let x represent the length of each of the two equal sides. This means that the total length of the two longer sides is 2x.
Let y represent the length of the third side.
The perimeter of a triangle is expressed as the sum of the length of each side of the triangle. The perimeter of the isosceles triangle is 65 centimeters. It means that
2x + y = 65 - - - - - - - - - 1
Each of the equal sides is 10 centimeters longer than the third side. This means that
x = y + 10
Substituting x = y + 10 into equation 1, it becomes
2(y + 10) + y = 65
2y + 20 + y = 65
2y + y = 65 - 20
3y = 45
y = 45/3 = 15
Substituting y = 15 into x = y + 10, it becomes
x = 15 + 10 = 25
If Micael is 2 years older than sam and sam is 15 than than micael is 17
Answer:
<h3>96 is the answer. </h3>
Step-by-step explanation:
<h3>The L.C.M of 8 and 12 is 24</h3><h3>The H.C.F of 8 and 12 is 4</h3>
<h3>We multiply </h3><h3>24 *4 we shall get 96 as the answer. </h3><h3 />
