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amid [387]
3 years ago
10

Help me with this please

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0

Answer:

The coordinate of M ( 4.5,6.5)

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15 POINTS!!! (16*4^3*8^8)^5 Find the answer and show work how you got it
777dan777 [17]

Answer:

2^170

Step-by-step explanation:

(16 x 4^3 x 8^8)^ 5

- start by converting it all to a common base

(2^4 x 2^3 x 2^24)^5

- calculate the product, by adding all the powers

(2^34)^5

= 2^170

5 0
3 years ago
Read 2 more answers
A professor grades students on four tests, a term paper, and a final examination. Each test counts as 15% of the course grade. T
alina1380 [7]

Answer:

The Alans's average for the course is 84.5

Step-by-step explanation:

We are given

There are 4 tests, A Term paper and a Final examination.

Score = 92, 78, 82, 90.

Term paper score = 80

Final examination score = 86

Weighted mean = ∑ w.f/∑w

     also the sum of all the weights is 100% = 1

weighted mean = 15%*92 + 15%*78+15%*82+15%*90+20%*80+20%*86/1

                         = 51.3 + 33.2

                         =  84.5

Therefore the Alans's average for the course is 84.5

5 0
3 years ago
3(x+5) - 3 = 2(3x + 1) - 3 <br> how many solutions does this equation have?
sleet_krkn [62]

Answer:

Step-by-step explanation:

1 solution: x=13/3

6 0
3 years ago
A force of 10 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work is done in stretching it
Troyanec [42]

Answer:

W = 15/4 ft . ib

Step-by-step explanation:

Force = 10ib

According to hooked law, f(x) = kx

x = 4inches = 4/12 ft

x= 1/3ft

f(x) = 1/3k

10 = 1/3k

k = 30 ib/ft

f(x) = 30x

Workdone = integral of f(x) with its limit

6 inches = 6/12 ft

= 1/2ft

W = integral(1/2 to 0) of 30x

W = 15x^2(1/2 to 0)

W = 15(1/2)^2 - 15(0)^2

W = 15(1/4) - 0

W = 15/4 ft. Ib

4 0
3 years ago
Aluminium has a density of 2.7g/cc .The density of 15cc<br> of Aluminium is
zysi [14]

Answer:

Step-by-step explanation:

Density = mass/volume.

Therefore.

2.7g/cc = x/15cc

x = 2.7x 15

x = 40.5g.

4 0
3 years ago
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