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JulijaS [17]
4 years ago
11

Rewrite the expression in the form k x z^n.

B2z%7D%5E%7B2%7D%20" id="TexFormula1" title="10 \sqrt[3]{z} \div {2z}^{2} " alt="10 \sqrt[3]{z} \div {2z}^{2} " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
Aleonysh [2.5K]4 years ago
4 0

Answer: 5z^(-5/3)

Step-by-step explanation:

Given the expression above, rewrite in the form k × z^n

(10 × (z)^1/3) ÷ 2z^2

(10z^1/3) ÷ (2z^2)

10/2(z^(1/3 - 2))

5z^(-5/3)

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3 years ago
The sum of the first k terms in the sequence is 118096, find the value of k. The first term is 78732 the common ratio is 1/3.
FrozenT [24]

Answer:

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Step-by-step explanation:

The sum of k terms of a geometric sequence with first term a1 and common ratio r is given by ...

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For the given numbers, this is ...

... 118096 = 78732·(1 -(1/3)^k)/(1 -1/3)

Manipulating this to get the term containing k, we have

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8 0
3 years ago
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6 0
4 years ago
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