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3 years ago

Divide the reciprocal of 5/6 by the reciprocal of the reciprocal of 5/6

Mathematics

2 answers:

miskamm [114]3 years ago

8 0

1. Divide the 5 by the 5, then the 6 by the 6.

ziro4ka [17]3 years ago

5 0

Reciprocal of the reciprocal of: cancels out the reciprocal because it occurs twice

5/6 ÷ 5/6
= 5/6 × 6/5
= 1

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dedylja [7]

We have

$\left(\dfrac{2}{3}\right)^x=\dfrac{2^x}{3^x}$

And we want

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Another way to read it is

$\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4=\left(\dfrac{2}{3}\right)^x$

It should be clear that the solution is $x=4$

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An SRS of ten brands of breakfast cereals is tested for the number of calories per serving. The following data result: 185, 190,

Pepsi [2]

Using the t-distribution, as we have the standard deviation for the sample, it is found that the 95% confidence interval estimate for the mean number of calories for servings of breakfast cereals is (195.3, 215.7).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.
t is the critical value.
n is the sample size.
s is the standard deviation for the sample.

From the sample and the significance level of 0.05, we have that the parameters are given by:

$\overline{x} = 205.5, s = 14.2, n = 10, t = 2.2622$

Hence:

$\overline{x} - t\frac{s}{\sqrt{n}} = 205.5 - 2.2622\frac{14.2}{\sqrt{10}} = 195.3$

$\overline{x} + t\frac{s}{\sqrt{n}} = 205.5 + 2.2622\frac{14.2}{\sqrt{10}} = 215.7$

The 95% confidence interval estimate for the mean number of calories for servings of breakfast cereals is (195.3, 215.7).

More can be learned about the t-distribution at brainly.com/question/16162795

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