Answer:
The rectangle has a width of 18 inches and a height length of 8 inches.
Step-by-step explanation:
The perimeter of a rectangle is described by the equation:

where <em>l</em> is width, <em>h</em> is height, and <em>p</em> is perimeter.
We're also told that the total perimeter is 52 inches.
We're also told that the length is six inches less than three times the width. We can express that as
.
We can plug that definition of w into the perimeter equation to find the length:

Now we can take that and the given perimeter, and substitute those into the perimeter equation to find the width:

So the width is 18
Answer:
16 feet in length.
Step-by-step explanation:
In this situation, you are given the area and the width of the full carpet, furthermore, you must reverse the formula for area to find the length, as so:
<u>Area Formula</u>: A=<em> l • w</em>
<u>Given</u>: 136= <em>l</em> • 8.5
<em>l</em> = 136 ÷ 8.5
<em>l</em> = 16 feet
I hope this was helpful!
Answer:
Step-by-step explanation:
The perpendicular lines have opposite reciprocal slopes.
<u>The given line has a slope of:</u>
<u>The perpendicular slope is:</u>
<u>And its y-intercept is:</u>
<u>The line is:</u>
<u>Convert this into standard form and compare with answer choices:</u>
- 3y = 2x + 21
- - 2x + 3y = 21
Correct choice is A
Find the area of the parallelogram, find the area of the triangle, then subtract the triangle's area from the area of the parallelogram.
Area of Parallelogram:
A= base * height
A= 20 in * 10 in
A= 200 in^2
Area of Triangle:
A= 1/2 base * height
A= 1/2 (10 in)(9 in)
A= 1/2 (90)
A= 45 in ^2
Area of Poster Left:
subtract the difference
A= Parallelogram Area - Triangle Area
A= 200 in^2 - 45 in^2
A= 155 in^2
ANSWER: 155 in^2 is the area of the poster board she has left.
Hope this helps! :)
Answer:

Step-by-step explanation:

In order to simplify the above expressions we make sure that we get same powers of 10 for both the terms.
So, we multiply and divide the first term with 10
Dividing first term by 10.

Now multiplying it by 10.

Evaluating the new expressions.

Taking
common factor out.

