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3 years ago

A recipe calls for 1 1/2 tablespoons of cinnamon would you need ANY WRONG ANSWER WIL BE REPORTED

Mathematics

1 answer:

erik [133]3 years ago

7 0

Cinnamon is needed because it gives a flavor so yes you should use it unless you hate cinnamon or are allergic to it.

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The equation of the perpendicular bisector of the line segment from (2,3)to (6,9) is

meriva

Y= -2/3x +26/3 First find the slope of the given points. The use the opposite reciprocal for the new slope. Find the midpoint of the given points. Use this ordered pair with your new slope. Plug into y=Mc+b to find b. Then rewrite using the new m and b.

4 0

2 years ago

Multiply these two together in simplest from

bezimeni [28]

Answer:

$\frac{3x}{5(x+2)}$

Step-by-step explanation:

Multiply the fractions by multiplying the numerators.

$\frac{6x^2}{x(x-3)} * \frac{(x-3)}{10(x+2)} \\\\\frac{6x^2(x-3)}{10x(x-3)(x+2)} \\\\ \frac{6x}{10(x+2)} \\\\\frac{3x}{5(x+2)}$

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3 years ago

Select the factors of 6ab + 3ay − 2bx − xy.

V125BC [204]

Answer
A. (3a − x)(2b + y)

cause

 (3a − x)(2b + y) = 6ab + 3ay -2bx -xy (expand by using distributive property)

3 0

2 years ago

Read 2 more answers

Triangle EFG has the following vertices E(1,2), F(4,2) and G(1,6). What are the new coordinates of triangle E’F’G’ after it is r

Fynjy0 [20]

Answer:

i dont know but

Step-by-step explanation:

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7 0

2 years ago

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

Solution:

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

2 years ago