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klasskru [66]
3 years ago
10

Graphing Lines How would you graph 10x-3y=15

Mathematics
1 answer:
kobusy [5.1K]3 years ago
8 0
Multiply 10x3 10 ⁢ x 3 by 1 1 to get 10x3 10 ⁢ x 3 . Divide 15 15 by −3 - 3 to get −5 - 5 . Use the slope-intercept form to find the slope and y-intercept. The slope-intercept form is y=mx+b y = m ⁢ x + b , where m m is the slope and b b is the y-intercept.
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A bag contains 4 white beads, 6 red beads, and 5 yellow beads. One bead is selected and not replaced. Then another bead is selec
lara31 [8.8K]

Answer:

\frac{24}{210}

Step-by-step explanation:

Add them all up 15 if one is taken out and no replaced OR put back in, then the second draw will have 14 beads.

4 x 6 = 24

15 x 14 = 210

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2 years ago
Topic 1 performance assessment pg. 53 and 54
777dan777 [17]
What are u talking about? i don't have an performance assessment of any kind 
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3 years ago
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What is the number of liters in 90 gallons
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6 0
3 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
What is the length of EF in the right triangle below?
Vinil7 [7]
Your question does not give enough information for me to answer
8 0
2 years ago
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