The third answer is correct.
Answer:
1. Perpendicular
2. Isosceles
3. Never
Step-by-step explanation:
1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.
2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )
In Δ COB , By using pythagoras : BC² = OC² + OB² ..........( 2 )
But, OA = OC because both are radius of same circle
So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC
⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.
3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius
Answer:
The midpoint of the given coordinates is
.
Step-by-step explanation:
We have given two coordinates (3,15) and (20,8).
Let we have given a line segment PQ whose P coordinate is (3,15) and Q coordinate is (20,8).
We have to find out the mid point M(x,y) of the line segment PQ.
Solution,
By the mid point formula of coordinates, which is;

On substituting the given values, we get;

We can also say that 
Hence The midpoint of the given coordinates is
.
Answer:
2.02 may be I thinks tell me if it's right