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3 years ago

1. The square root of 70 is between what two numbers?

Mathematics

2 answers:

Firlakuza [10]3 years ago

8 0

B is conrrect because the square root of 70 is 8.3666.

horsena [70]3 years ago

3 0

Yes the answer is B. Like the comment above

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25.7% as a fraction<br> plz help

vlada-n [284]

Answer:

257/1000

Step-by-step explanation:

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3 years ago

Write an expression that shows how to use the halving and doubling strategy to find 28✖️50

Sonja [21]

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3 years ago

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13+39-2-10-6 power2 orders of operation

Advocard [28]

6 to the power of 2 is 6 multiplied by six which is 36
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3 years ago

An ice cream cone has a diameter of 3 inches.The distance from the top of the cone to the point at the bottom (height) is 5 inch

solong [7]

Answer:

11.781 cubic inches (round accordingly)

Step-by-step explanation:

The formula for the volume of a cone is:

$V=\frac{1}{3}\pi r^{2} h$

where r is the radius and h is the height.

For our ice cream cone:

d = 3 inches

r = 1.5 inches (the radius is half of the diameter)

h= 5 inches

So all we have to do is plug in our values and solve for the volume:

$\frac{1}{3}\pi (1.5)^{2}(5) = 11.781$

So our final answer is around 11.8 cubic inches.

3 0

3 years ago

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

3 years ago