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3 years ago

1. The square root of 70 is between what two numbers?

Mathematics

2 answers:

Firlakuza [10]3 years ago

8 0

B is conrrect because the square root of 70 is 8.3666.

horsena [70]3 years ago

3 0

Yes the answer is B. Like the comment above

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Use the drop-down menus to identify the key values of the box plot. The median is . The minimum is . The maximum is . The lower

Elenna [48]

Answer:

median-c

minimum-a

maximum-e

Q1-b

Q2-d

6 0

3 years ago

Read 2 more answers

Find the missing side round your answer to the nearest tenth

kap26 [50]

Use trigonometric ratios.
Use angle(19)
Adjacent side of angle measure 19 is X
The hypotenuse is 21.
Use the cosine
Cos(19)=x/21

Plug in calculator
(21)cos(19)=19.85

Round to the nearest tenth. Which means the 8 rounds up to 9.

Answer: 19.9

7 0

3 years ago

Instructions: Given the following constraints, find the maximum and minimum values for z.

loris [4]

Answer:

$x+3y\leq 0$

$x-y\geq 0$

$1) x+3y=0$

$x-y=0$

$-----$

$4y=0$

$y=0$

$x=0$

$(0,0)$

$2)(x+3y=0)3$

$3x-7y=16$

$3x+9y=0$

$3x-7y=16\\------\\16y=-16$

$y=-1$

$(3,-1)$

$3)(x-y=0)3$

$3x-7y=16$

$3x-3y=16$

$3x-3y=0$

$3x-7y=16\\------\\4y=-16$

$y=-4$

$x=4$

$(4,-4)$

$Z=-x+5y$

$(0,0):z=0$

$(3,-1):z=-8$

$(4,-4):z=-24$

$Maximum \:Value\: of\: z:0$

$Minimum\: Value\: of\: z:-24$

<u>OAmalOHopeO</u>

8 0

3 years ago

Two numbers have a GCF of 6 one is 24 the other number is less than 30 what could the other number be ?

Oksana_A [137]

The other number could be 6. The GCF of 6 and 24 is 6, and 6 is less than 30.

6 0

3 years ago

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

<u>Step-by-step explanation:</u>

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

3 years ago