Answer:
y=0
Step-by-step explanation:
6y+2=-2(2y-1)
Distribute
6y+2 = -4y +2
Add 4y to each side
6y+2 = -4y +2+4y
6y +2 =2
Subtract 2 from each side
6y +2-2 = 2-2
6y = 0
y=0
Lily made $75.36 more than Layla did. If Layla raised her price to $1.00, she would still not make more money than Lily.
Use a proportion to find the number of cupcakes Lily makes in 8 hours. She bakes 7 cupcakes in 10 minutes; we want to know how many she makes in 8(60)=480 (since there are 8 hours and each hour is 60 minutes):
7/10 = x/480
Cross multiply:
7*480 = 10*x
3360 = 10x
Divide both sides by 10:
3360/10 = 10x/10
336 = x
Lily bakes 336 cupcakes.
She sells 2/3 of these; 2/3(336) = 2/3(336/1) = 672/3 = 224 cupcakes sold.
Each cupcake is sold for $1.29; 224(1.29) = 288.96
To find the number of cupcakes Layla makes in 8 hours, we set up a different proportion. We know she bakes 8 cupcakes in 12 minutes; we want to know how many she bakes in 8(60) = 480 minutes:
8/12 = x/480
8*480 = 12*x
3840 = 12x
Divide both sides by 12:
3840/12 = 12x/12
320 = x
She bakes 320 cupcakes. She sells 75% of those; 75% = 75/100 = 0.75:
0.75(320) = 240
Each of those 240 cupcakes sells for $0.89:
0.89(240) = 213.60
This means Lily makes 288.96-213.60 = 75.36 more than Layla.
If Layla raised her price to $1.00, she would make 1(240) = $240; this is still less than Lily.
Using PEMDAS the you start with parentheses and exponents 4x4 would be 16 times 2 is 32 plus 5 is 37 then multiply that by 3 = 111 subtract 10 and get 101
P + 10 = 20 Subtract 10 from both sides
P = 10
Substitute P = 10 into P + Q = 16
P + Q = 16 Plug in 10 for P
10 + Q = 16 Subtract 10 from both sides
Q = 6
Answer:
a) P=0
b) P=1
c) P=0
d) X=7.1645
Step-by-step explanation:
We have the pH of soil for some region being normally distributed, with mean = 7 and standard deviation of 0.10.
a) What is the probability that the resulting pH is between 5.90 and 6.15?
We calculate the z-score for this 2 values, and then compute the probability.
Then the probability is
b) What is the probability that the resulting pH exceeds 6.10?
We repeat the previous procedure.
c) What is the probability that the resulting pH is at most 5.95?
d. What value will be exceeded by only 5% of all such pH values?
We have to calculate the value of pH for which only 5% is expected to be higher. This can be represented as P(X>x)=0.05.
In the standard normal distribution, it happens for a z=1.645.
Then, we can calculate the pH as:
