Answer: 336 cm²
Step-by-step explanation:
A trapezoid looks like a rectangle with 2 traingles attached to the side, yeah? So imagine cutting off those 2 triangles. In the middle you have a rectangle with the dimensions of 14 cm by 16 cm. The area of that rectagle is 224 cm². By subtracting the top base length from the bottom base length, you get the length of the two triangles. So, it would be 28 cm - 14 cm, giving you 14 cm. There were 2 triangles, so cut that length in half and you get 7 cm for the base of one traingle. To find the area of 1 traingle, you would do 1/2 multiplied by 7 multiplied by 16. But you have 2 triangles. so the 1/2 step isn't needed because if you put the two triangles together, you get a new rectangle. Thus, when you add the area of this new rectangle, you get 112 cm². Add this to the original rectangle, and your final area is 336 cm².
ANSWER
The restrictions are
EXPLANATION
We were given the rational function,
The function is defined for all values of a, except
This has become a quadratic trinomial, so we need to split the middle term.
We do that by multiplying the coefficient of 
which is 5 by the constant term which is 3. This gives us 15.
The factors of 15 that adds up to 16 are 1 and 15.
We use these factors to split the middle term.
We now factor to get,
We factor further to get,
This implies that,
This gives
These are the restrictions.
Answer- 971.76 yd^3 (btw I used pi not 3.14)
Explanation:
Solve for the volume of the cone
V=pi*r^2*h/3
V=pi*10^2*22/3
V= 2408.55
Next solve for the volume of the sphere
V=4/3*pi*r^3
V=4/3*pi*7^3
V=1436.76
The last step it to subtract the volume of the sphere from the volume of the cone
2408.55-1436.76=971.76
Answer:
a. P(E) = 1033/ 2851=0.3623
P(R) = 854/2851=0.2995
P(D) = 964/2851=0.3381
P(E ∩ D) = P(E) +P(D)= 0.3623 +0.3381= 0.7004
(d) 0.423 158
Step-by-step explanation:
a. P(E) = 1033/ 2851=0.3623
P(R) = 854/2851=0.2995
P(D) = 964/2851=0.3381
(b) Are events E and D mutually exclusive?
Yes these events are mutually exclusive. If students are deferred they may be admitted later but not early. Mutually Exclusive or disjoint events do not occur at the same time.
P(E ∩ D) = P(E) +P(D)= 0.3623 +0.3381= 0.7004
(c) For the 2,375 students who were admitted, the probability that a randomly selected student was accepted during early admission is
P(E) = 1033/ 2851=0.3623
P(E) + P(D for later admission) =0.3623 + 18%*0.3381
=0.3623 + 0.0609 = 0.423 158
