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nirvana33 [79]
3 years ago
9

Need help Identify three solutions of the graph shown

Mathematics
1 answer:
tester [92]3 years ago
6 0
The solutions are basically the points on the graph that the line passes through. The best way to pick them is to use the whole numbers that are on the corners of the little boxes instead of the middle.

(4, -5)
(3, -3)
(1, 1)
(0, 3)
(-1, 5)
and so on.
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On a map of Arizona, the scale is 1 inch = 5 inches. The distance between Brady's house and Flagstaff is 23 inches on the map. W
sladkih [1.3K]

So we know that 1 inch on the map = 5 inches.

So if Brady's house is 23 inches away from Flagstaff on the map:

23 * 5 = 115.

So 115 inches is the actual distance...

Wait. His house is 9 feet away from Flagstaff? That's cool.

7 0
3 years ago
HURRY!!
ankoles [38]

Answer: A. 8x+13

Step-by-step explanation:

9+4(2x-1)+8

Use distributive property

9+8x-4+8

Combine like terms

8x+13

4 0
3 years ago
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(HELP!!!) Gustavo invests £520 for 6 years in a bank account paying simple interest. At the end of 6 years, the amount in the ba
romanna [79]
629.20/520=1.21
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A company manufacturers video games with a current defect rate of 0.95%. To make sure as few defective video games are delivered
RSB [31]
There would be about 19 defective products delivered.

First, let's start with the number of defective games. 
100000 x 0.0095 = 950

Now, the test will catch 98% of those defects. That means 2% of the defects will get through to the consumers.
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3 0
3 years ago
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What is the probability that a point chosen at random in the given figure will be inside the larger square and outside the small
liraira [26]

Answer:

  • 51/100

Step-by-step explanation:

<em>The probability that a point chosen at random in the given figure will be inside the larger square and outside the smaller square</em> is equal to the ratio of the area of interest to the total area:

<em>P(inside larger square and outside smaller square)</em> = area of interest / total area

<em>P(inside larger square and outside smaller square)</em> = area inside the larger square and outside the smaller square / area of the larger square

<u>Calculations:</u>

<u />

1. <u>Area inside the larger square</u>: side² = (10 cm)² = 100 cm²

2. <u>Area inside the smaller square </u>= side² = (7cm)² = 49 cm²

3. <u>Area inside the larger square and outside the smaller square</u>

  • 100 cm² - 49 cm² = 51 cm²

4.<u> P (inside larger square and outside smaller squere)</u>

  • 51 cm² / 100 cm² = 51/100
5 0
3 years ago
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