NEED HELP What is the real value of x in the equation log.2.24 - log.2.3 = log.5.x ?
2 answers:
Answer:
125
Step-by-step explanation:
log2 (24) - log2 (3) = log5 (x)
We know that log a(b) - log a(c) = log a( b/c)
log2 (24/3) = log5 (x)
log2 (8) = log5 (x)
Rewriting 8 as 2^3
log2 (2^3) = log5 (x)
We know that log a ( a^b) = b loga (a) and loga (a) =1
3 log2 (2) = log5 (x)
3 *1 = log5 (x)
3 = log5 (x)
We know log a (b) =c can be written as a^c =b
5^3 = x
125 =x
Answer:
x = 125
Step-by-step explanation:
log2(24) - log2(3) = log5(x)
log2(8×3) - log2(3) = log5(x)
log2(8) + log2(3) - log2(3) = log5(x)
log(8) = log5(x)
log2(2³) = log5(x)
3log2(2) = log5(x)
3 = log5(x)
x = 5³
x = 125
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Answer: 45/100
Step-by-step explanation: .45 as a fraction is 45/100
Answer:
I think answer is
5.X+11
Answer:
Explanation:
given that y = 2
using quadratic formula:
in decimals:
To be a function each x-value (input) should have only one y-value (output). Here you can see when x=2 it has an output of either 5 or 1. Therefore, the relation is NOT a function.
Hope this helps!!!!!!!!!!
