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pychu [463]
3 years ago
8

One building is 15 feet tall and another is 90 feet tall. Proportionally, the height of the smaller building is A) 1/6 the hight

if the larger building b) 1/9 the height of the larger building c) 3/4 the height of taller building d) 6 times the height of the larger building
Mathematics
2 answers:
egoroff_w [7]3 years ago
8 0

The answer will take the form: height smaller building = ? · height larger building, with ? = k. Already, you should be able to see that k must be less than 1. 15 feet = k (·) 90 feet; k =  15 /90  =  1/ 6   the height of the larger building.

GalinKa [24]3 years ago
5 0

Answer:

Option A is the correct choice.

Step-by-step explanation:  

We have been given that one building is 15 feet tall and another is 90 feet tall. We are asked to find the height of smaller building proportionally.

Since heights of both buildings are proportional so we will use proportions to find the height of smaller building in terms of height of larger building.  

\frac{\text{Height of smaller building}}{\text{Height of larger building}}=\frac{15}{90}

\text{Height of smaller building}=\frac{1}{6}\times {\text{Height of larger building}

We can see that height of smaller building is 1/6 of the height of larger building, therefore, option A is the correct choice.

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Read 2 more answers
A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 84 in. What are
Lesechka [4]

Answer:

a) \frac{28}{\pi} in

b) 28 in

c) 784 in²

Step-by-step explanation:

Let the length be 'L'

and the radius be 'r'

Thus, according to the question

L + 2πr = 84 in

L = 84 - 2πr   ............(1)

Volume of the cylinder, V = πr²L

substituting the value of L from 1, we get

V =  πr²(84 - 2πr)

or

V = 84πr² - 2π²r³

for points of maxima, differentiating the above equation and equating it to zero

\frac{dV}{dr}=\frac{d(84\pi r^2-2\pi^2 r^3))}{dr}

or

2(84)πr - 3(2)π²r² = 0

or

2πr(84 - 3πr) = 0

or

r = 0    and    84 - 3πr = 0

or

⇒ 3πr = 84

or

⇒ r = \frac{28}{\pi} in

since, the radius cannot be zero therefore, r = 0 is neglected

Therefore,

a) The radius of the largest cylindrical package = \frac{28}{\pi} in

b) from  (2)

L = 84 - 2πr

or

⇒ L = 84 - 2\pi\times\frac{28}{\pi}

or

⇒ L = 84 - 56 = 28 in

The length of the largest cylindrical package = 28 in

c ) The volume of the largest cylindrical package ,V = πr²L

= \pi\times\frac{28}{\pi}\times28

= 784 in²

7 0
3 years ago
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