5/6 of a number cannot be greater than the number
        
                    
             
        
        
        
I so understand that doesn't mean I so
        
             
        
        
        
Hi there! 
To solve this problem, we need to set up two equations and use the system of equations to solve.
Let x be the first number. 
Let y be the second number. 
(x + y) ÷ 2 = 34
x = 3y
Now, we can use substitution to solve.
(3y + y) ÷ 2 = 34
4y ÷ 2 = 34
2y = 34
y = 17
Now, we plug the value of y in the equation to solve for x. 
x = 3*17
x = 51
Hope this helps!
        
             
        
        
        
 The volume of the solid of revolution is approximately 37439.394 cubic units.
<h3>
How to find the solid of revolution enclosed by two functions</h3>
Let be  and
 and  , whose points of intersection are
, whose points of intersection are  ,
,  , respectively. The formula for the solid of revolution generated about the y-axis is:
, respectively. The formula for the solid of revolution generated about the y-axis is:
 (1)
 (1)
Now we proceed to solve the integral: 
 (2)
 (2)

![V = 6\pi \left[(y-1)\cdot \ln y\right]\right|_{1}^{e^{35/6}}](https://tex.z-dn.net/?f=V%20%3D%206%5Cpi%20%5Cleft%5B%28y-1%29%5Ccdot%20%5Cln%20y%5Cright%5D%5Cright%7C_%7B1%7D%5E%7Be%5E%7B35%2F6%7D%7D)
![V = 6\pi \cdot \left[(e^{35/6}-1)\cdot \left(\frac{35}{6} \right)-(1-1)\cdot 0\right]](https://tex.z-dn.net/?f=V%20%3D%206%5Cpi%20%5Ccdot%20%5Cleft%5B%28e%5E%7B35%2F6%7D-1%29%5Ccdot%20%5Cleft%28%5Cfrac%7B35%7D%7B6%7D%20%5Cright%29-%281-1%29%5Ccdot%200%5Cright%5D)


The volume of the solid of revolution is approximately 37439.394 cubic units. 
To learn more on solids of revolution, we kindly invite to check this verified question: brainly.com/question/338504
 
        
             
        
        
        
Step-by-step explanation:
0.5 > 0.2 > -6
as every positive integer is greater than negatively integer.
<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care</u></em><em><u>!</u></em>