Answer:
The number of liters of 50% antifreeze solution is 50 and the number of liters of 90% antifreeze solution is 150
Step-by-step explanation:
Let
x ----> number of liters of 50% antifreeze solution
y ----> number of liters of 90% antifreeze solution
we know that
50%=50/100=0.50
90%=90/100=0.90
80%=80/100=0.80
x+y=200
x=200-y ------> equation A
0.50x+0.90y=0.8(200) -----> equation B
substitute equation A in equation B and solve for y
0.50(200-y)+0.90y=160
100-0.50y+0.90y=160
0.40y=160-100
0.40y=60
y=150 liters
Find the value of x
x=200-y
x=200-150=50 liters
therefore
The number of liters of 50% antifreeze solution is 50
The number of liters of 90% antifreeze solution is 150
Answer:
34
Step-by-step explanation:
Marcy got 15% of the 40 wrong
.15 *40
6
If she got 6 wrong, then she got the rest right
40-6 = 34
She got 34 right
The first one YES and the last one NO!
60-12-18-2-8=20
=48-18-2-8
=30-2-8
=28-8
=20
So, 20 students don't take either of these subjects.
For this case we have the following expression:
(x ^ 2 + 2x + 1 / x ^ 2-8x + 16) / (x + 1 / x ^ 2-16)
Rewriting we have:
(((x + 1) (x + 1)) / ((x-4) (x-4))) / (x + 1 / ((x + 4) (x-4)))
Then, we cancel similar terms:
((x + 1) / (x-4)) / (1 / (x + 4))
Rewriting:
((x + 1) (x + 4)) / (x-4)
Answer:
((x + 1) (x + 4)) / (x-4)