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3 years ago

a restaurant needs to buy 367 new plates in it, if each box has three plates in it, how how many boxes will they need to buy?

Mathematics

2 answers:

Nataliya [291]3 years ago

7 0

122remainder1 Because you have to do 3 divided by 367 which equals 122remainder1.

Kruka [31]3 years ago

6 0

You need to divide 367 by 3 = 122.3 but you cant have .3 of a box so this needs to be rounded up to 123 as even though this will be more than the needed amount, it is the minimum amount needed.

To double check:

123 x 3 = 369.
So they will have 2 spare.

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4 is what percent of 17?

solong [7]

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3 years ago

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Rewrite the equation in standard form y = - 3/4 x - 6

notka56 [123]

Answer:

Step-by-step explanation:

$y =\dfrac{-3}{4}x -6$

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2 years ago

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2 years ago

There are 40 students,

egoroff_w [7]

answer

$\frac{621}{2000}$ ≈ 0.31 = 31 %

set up equation

the probability of someone from the first group having brown eyes is $\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }$

the probability of someone from the second group having brown eyes is $\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }$

so the probability of both students having brown eyes is $\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }$ * $\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }$

values

students with brown eyes in first group = 27

total students in first group = 40

students with brown eyes in second group = 23

total students in second group = 50

plug in values and solve

$\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }$ * $\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }$

= $\frac{27}{40} *\frac{23}{50}$