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dlinn [17]
3 years ago
12

Find the LCM= Least common multiple for these two sets of numbers. ​

Mathematics
1 answer:
Rainbow [258]3 years ago
4 0

Answer:

number 1 is 10 and number 2 is 72

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The net change for a certain stock is the dollar value change in the stock's closing price from the previous day's closing price
Natali [406]
-3 has the greatest absolute value.
7 0
3 years ago
Country days scholarship rounds receive a gift of $135000. The money is invested in stock, bonds, and CDs. CDs pay 2.75% interes
Vsevolod [243]

Answer:

  • CDs — $10,000
  • bonds — $80,000
  • stocks — $45,000

Step-by-step explanation:

Let the variables c, b, s represent the dollar amounts invested in CDs, stocks, and bonds, respectively. Then the problem statement gives us 3 relations between these 3 variables:

  c + b + s = 135000 . . . . . . . . . . . . . . . . . total invested

  0.0275c +.045b +0.104s = 8555 . . . . . total income earned

  -c + b = 70000 . . . . . . . . . . . . . . . . . . . . . 70,000 more was in bonds than CDs

Using the third equation to write an expression for b, we can substitute into the other two equations.

  b = 70000 +c . . . . . . . . . . . . . . . . expression we can substitute for b

  c + (70000 +c) +s = 135000 . . . . substitute for b in the first equation

  2c +s = 65000 . . . . . . . . . . . . . . . . [eq4] simplify

  .0275c +.045(70000 +c) +.104s = 8555 . . . . . substitute for b in 2nd eqn

  .0725c +.104s = 5405 . . . . . . . . . . [eq5] simplify

Using [eq4], we can write an expression for s that can be substituted into [eq5].

  s = 65000 -2c . . . . . . . expression we can substitute for s

  0.0725c +0.104(65000 -2c) = 5405

  -0.1355c = -1355 . . . . . . . . . . . . . . . . . . . . subtract 6760, simplify

  c = 1355/.1355 = 10,000

  s = 65000 -2×10000 = 45,000

  b = 70000 +10000 = 80,000

The amounts invested in stocks, bonds, and CDs were $45,000, $80,000, and $10,000, respectively.

_____

Alternatively, you can reduce the augmented matrix for this problem to row-echelon form using any of several calculators or on-line sites. That matrix is ...

\left[\begin{array}{ccc|c}1&1&1&135000\\0.0275&0.045&0.104&8555\\-1&1&0&70000\end{array}\right]

6 0
3 years ago
A soup kitchen makes 15 gallons of soup each day a quarter of the soup is served and the rest is saved for the next day , what i
Sophie [7]

Number of ounces left is 1120

Step-by-step explanation:

  • Step 1: Find number of ounces left after each day.

Given total soup prepared each day = 15 gallons

Amount served each day = 1/4 of 15 = 15/4 gallons

Amount left after each day = 15 - 15/4 = 60 - 15/4 = 35/4 gallons

  • Step 2: Convert gallons into ounces. 1 gallon = 128 ounces

35/4 gallons = 35/4 × 128 = 1120 ounces

5 0
3 years ago
Find the equation for 4x/5=1/3(2x-15)
tia_tia [17]
4x / 5 = 1 / 3 ( 2x - 15 )
4x / 5= ( 2x - 15 ) / 3
4x × 3 = 5 ( 2x - 15 )
12x = 10x - 75
12x - 10x = - 75
2x = - 75
x = - 75 / 2
x = - 37.5
7 0
3 years ago
What is an equation of the line that passes through the points (4, -4) and<br> (-4,-4)?
aalyn [17]

Answer:

y=-4

Step-by-step explanation:

i think its right

4 0
3 years ago
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