Answer:
The proportion of children that have an index of at least 110 is 0.0478.
Step-by-step explanation:
The given distribution has a mean of 90 and a standard deviation of 12.
Therefore mean,
= 90 and standard deviation,
= 12.
It is given to find the proportion of children having an index of at least 110.
We can take the variable to be analysed to be x = 110.
Therefore we have to find p(x < 110), which is left tailed.
Using the formula for z which is p( Z <
) we get p(Z <
= 1.67).
So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)
Using the Z - table we can calculate p(Z < 1.67) = 0.9522.
Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478
Therefore the proportion of children that have an index of at least 110 is 0.0478
Step-by-step explanation:
you do one by one like 6 times the other 6 is 36 times the other six you get 212. then the othe rquestion you go 10•10 equal 100 u just equal eachother
Answer:
0.02841 and 3.953
Step-by-step explanation:
Answer:
The answer to your question would be Thinking at the Margin.
Cheers!
Step-by-step explanation:
A) -9
-7(x+9)=9(x-5)-14x
-7x-63=9x-45-14x
-45 -45
-7x-18=9x-14x
+7x +7x
-18=9x+7x-14x
-18=2x
(-18)/2=(2x)/2
-9=x