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never [62]
3 years ago
9

What is the missing fact in this fact family 7+5 =12 , 12-5=7 , 12-7=5

Mathematics
2 answers:
alexandr1967 [171]3 years ago
8 0
Ima not sure bout my answer but maybe it might be 5+7=12
n200080 [17]3 years ago
5 0
Missing fact is 13 seats are empty
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I am a number between 20 and 30. I am not divisible by 6. and the sum of my factors is 31. What number am I?
Soloha48 [4]
The answer to the question is 25.
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4 years ago
What is the positive solution to the equation 0 = -x2 + 2x + 1?
sergiy2304 [10]
I think is c that what i think
3 0
3 years ago
2x+3=-7<br><br> What is the answer?
Mashcka [7]

Hi there! With equations like this we want to get our variable on one side and and our constant on the other.

So with 2x + 3 = -7 you'd subtract the constant 3 from both sides of the equal sign to get 2x = -10, then you'd divide both sides by 2 to get x = -5. If you double check your work by replacing x in the original equation with our answer we'd find that 2(-5) + 3 = -7 is correct.

Hope you find this helpful :)

4 0
3 years ago
What is the correct maximum or minimum for the function f(x) = -|x-2| + 1
Usimov [2.4K]

Answer:

1

Step-by-step explanation:

The graph is shifted up one unit

5 0
2 years ago
Read 2 more answers
Need help pleaseI was bad at math in school so lwant to learn
aleksklad [387]

The probability of an event is expressed as

Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}

Given:

\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}

The probability of drwing two blue balls one after the other is expressed as

Pr(\text{blue)}\times Pr(blue)

For the first draw:

\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}

The probability of drawing two blue balls one after the other is evaluted as

\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}

The probablity that none of the balls drawn is blue is evaluted as

\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}

Hence, the probablity that none of the balls drawn is blue is evaluted as

\frac{20}{21}

8 0
1 year ago
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