Question

(09.04 LC) A circle is centered at (5, −9) and has a radius of 12. Which of the following is the equation for this circle? (6 points)
Group of answer choices: (a). (x − 5)^2 + (y + 9)^2 = 144
(b). (x + 5)^2 + (y − 9)^2 = 144
(c). (x + 5)^2 + (y − 9)^2 = 12
(d). (x − 5)^2 + (y + 9)^2 = 12

Answer 1

Answer:

Option a $(x-5)^2+(y+9)^2=144$

Step-by-step explanation:

we know that

The equation of a circle in standard form is

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center of the circle

r is the radius

In this problem we have

$(h,k)=(5,-9)\\r=12\ units$

substitute in the equation

$(x-(5))^2+(y-(-9))^2=12^2$

$(x-5)^2+(y+9)^2=12^2$

$(x-5)^2+(y+9)^2=144$